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Gnoma [55]
3 years ago
8

A card is chosen at random from a standard deck of 52 cards. What is the probability that the card is a Queen or a $\diamondsuit

$ (or both)?
Mathematics
1 answer:
DochEvi [55]3 years ago
3 0

Answer:

probability that the card is a Queen or a diamond= 0.3269

Step-by-step explanation:

There are 4 queen in a deck of cards and 13 diamond in a deck of cards.

And a deck of cards contains 52 cards total.

Probability of the card selected to be a queen = number of queen/total number of cards

Probability of the card selected to be a queen =4/52

Probability of the card selected to be a queen= 1/13

Probability of the card selected to be a diamond= number of diamond/ total number of cards

Probability of the card selected to be a diamond=13/52

Probability of the card selected to be a diamond=1/4

probability that the card is a Queen or a diamond= Probability of the card selected to be a queen + Probability of the card selected to be a diamond

probability that the card is a Queen or a diamond= 1/13+1/4

probability that the card is a Queen or a diamond= 0.3269

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castortr0y [4]
The answer is: y = -2x+12

4x+2y=24=

4x-4x+2y=24-4x=

2y=24-4x

Divide each piece by 2=

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y=12-2x

But, slope intercept form is y=mx + b so you must put the second part in reverse, making the answer to the equation be y=-2x+12
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6 0
3 years ago
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Given that GJ=70.2, JH=26, and GK=70.2, find the measure of JK
pychu [463]

Answer:

52

Step-by-step explanation:

The two sides (GJ and GK) are congruent, and the angle of ∠GHJ is 90°.

It means JH ≅ HK.

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26 x 2 = 52

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5 0
3 years ago
Lee class has 1.4 times as many students as Fred's. If there are 60 students, how many students does Fred's class have? How many
slava [35]
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8 0
4 years ago
Adult tickets to the fall play cost $8 and student tickets cost $4. the drama class sold 20 more adult tickets than student tick
Ganezh [65]
Let a = Adult tickets, s = Student tickets; we are going to set up a system of equations. 

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We are going to multiply the second equation by so that we can cancel out one of the variables and solve for the other. This gives you:

8a + 4s = 880
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Now we plug in the amount of adult tickets to solve for the student ones.

75 - s = 20
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Divide both sides by - 1
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There were 55 student tickets sold and 75 adult tickets. 


6 0
3 years ago
Translate the sentence into an inequality.
blagie [28]

Let the no be x

Inequality given by

\\ \sf\longmapsto 2(x-4)\leqslant -18

Let's solve

\\ \sf\longmapsto x-4\leqslant -9

\\ \sf\longmapsto x\leqslant -5

3 0
3 years ago
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