Answer and explanation:
Please find answer and explanation attached
It should be y1 - y2/x1 - x2 this is supposed to be a fraction
I end up getting -31 - 24/5 + 6 or -31 -24/5 - (-6)
In private correspondence with the author of the question, it was determined
that 'y' is the variable of integration.
Therefore, 'a' is a constant for purposes of this integration, and that whole
'a' business can be taken outside the integral.
Integral [a/(1-ay) dy] = a/(1-a) integral [dy/y] = a ln(y)/(1-a) + C
The answer is:
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x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
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{Otherwise, the question might be "incomplete".}.
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The question seems incomplete; how can we solve for "x" when we do not know what "y" equals?
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However, it could be possible to "solve for x" in terms of "y". To so this, we need to isolate ""x" on one side of the equation:
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Given: <span>y=1/4 (x) + 3 ; Let us multiply the ENTIRE EQUATION (both sides) by "4", to get rid of the "1/4" (fraction coefficent) of "x", and to "cancel out" the "1/4" fraction cofficient of "x" to the implied "1"; to help solve for "x" :
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4 *{ </span>y= 1/4 (x) + 3} ;
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4y = x + 12 ; Now we can subtract "12" from EACH SIDE of the equation; to isolate "x" on one side of the equation; and to solve for "x":
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4y - 12 = x + 12 - 12 ;
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4y - 12 = x ; This is our answer:
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x = 4y - 12 ; (Assuming the problem meant to solve for "x"; "in terms of "y").
