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AURORKA [14]
3 years ago
8

Pablo's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Pablo $5.40 per pound, and type

B coffee costs $4.25 per pound. This month's blend used four times as many pounds of type B coffee as type A, for a total cost of $896.00. How many pounds of type A coffee were used?​
Mathematics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

solo se suma 5.40 estre 4,25

y el resultado que te d lo divides entre

896.00

Step-by-step explanation:

el resultado de estas operaciones es 537espero te sirva

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the government of India Today group to offer online learning to young people in the future of our country is the best of luck to you mam

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It took Sharon 105 minutes to wash three cars and put everything away. If she spent 10
shtirl [24]
Well that would be 105 - 10. If you spent 105 minutes in total and 10 of that was putting your stuff away, take that 10 minutes away and you’d get 95. So, she spent 95 minutes washing 3 cars in total. If you divide that 95 into 3s, you get rounded 31 minutes each.
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3 years ago
How is 7.54÷4= 1.88<br><br>I got 1.88 with the remainder of 2​
Naddika [18.5K]

Answer:

I got 1.885 for the answer.

Maybe they wanted it rounded to just 2 decimal places.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is the weight of an ice core that is 25 pounds on earth?
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3 years ago
A cardboard box without a lid is to have a volume of 19,652 cm3. Find the dimensions that minimize the amount of cardboard used.
Effectus [21]

Answer:

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

Step-by-step explanation:

Let the dimension of the cardboard box be x cm by y cm by z cm.

The surface area of the cardboard box without lid is

f(x,y,z)= xy+2xz+2yz.....(1)

Given that the volume of the cardboard is 19,652 cm³.

Therefore xyz =19,652

\Rightarrow z=\frac{19652}{xy}......(2)

putting the value of z in the equation (1)

f(x,y)=xy+2x(\frac{19652}{xy})+2y(\frac{19652}{xy})

\Rightarrow f(x,y)=xy+\frac{39304}{y})+\frac{39304}{x}

The partial derivatives are

f_x=y-\frac{39304}{x^2}

f_y=x-\frac{39304}{y^2}

To find the dimension of the box set the partial derivatives f_x=0 and f_y=0.Therefore y-\frac{39304}{x^2}=0

\Rightarrow y=\frac{39304}{x^2}.......(3)

and   x-\frac{39304}{y^2}=0

\Rightarrow x=\frac{39304}{y^2}.......(4)

Now putting the x in equation (3)

y =\frac {39304}{(\frac{39304}{y^2})^2}

\Rightarrow y=\frac{y^4}{39304}

\Rightarrow y^3= 39304

⇒y=34 cm

Then \Rightarrow x=\frac{39304}{34^2} =34 cm.

Putting the value of x and y in the equation (2)

z=\frac{19652}{34 \times 24}

  =17 cm.

The dimension of the cardboard is 34 cm by 34 cm by 17 cm.

4 0
3 years ago
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