The sum of three consecutive odd integers is 76 less then seven times the middle number. The three integers are 17, 19 and 21 respeectively
<h3><u>Solution:</u></h3>
Since each consecutive odd integer is separated by a difference of 2
Let "n" be the first integer
n + 2 be the second integer
n + 4 be the third integer
Given that the sum of three consecutive odd integers is 76 less then seven times the middle number
Which means,
The sum of ( n, n + 2, n + 4) is equal to 76 less than seven times the middle number ( 7(n + 2))
That is,
n + n + 2 + n + 4 = 7(n + 2) - 76
3n + 6 = 7n + 14 - 76
4n = 68
n = 17
So we get:
First integer = n = 17
Second integer = n + 2 = 17 + 2 = 19
Third integer = n + 4 = 17 + 4 = 21
Thus the three consecutive odd integers are 17, 19 and 21 respeectively
The coefficient of the x-term is -3. Add the square of half of that.
.. (-3/2)² = 9/4 . . . . . . the number you need to add.
x² -3x +9/4 = (x -3/2)²
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If the x² term has a coefficient other than 1, you need to factor that out first and deal with the remaining binomial. For example,
.. 2x² -6x = 2(x² -3x)
For this you would need to add 9/4 inside parentheses to get
.. 2(x² -3x +9/4) = 2(x -3/2)²
Of course, to keep the original value, you would need to subtract 2*(9/4) outside parentheses.
.. 2x² -6x = 2(x -3/2)² -9/2
<u>Answer </u><u>:</u>
This figure consists of two shapes that are a rectangle and a square . We will first find the area of rectangle then the square then add them . Let's work on this together ,
- Breadth of rectangle = 4 cm
- Length of rectangle = 4 + 5 + 3
- Length = 12 cm
- Area of rectangle = 12 × 4
- 48 cm²
Area of square ,
Total area of the figure ,
Answer:
A cylinder has parallel discs bases that are congruent in size.
Step-by-step explanation:
Answer:
The correct answer is A. and B.
Step-by-step explanation:
If it's flipped over to the other side, it will still be the same shape and the same size.
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