All categories

3 years ago

Four different stores have the same digital camera on sale. The original price and discounts offered by each store are

Mathematics

2 answers:

Schach [20]3 years ago

6 0

Answer:

yes it is d

believe me

i calculated

inysia [295]3 years ago

3 0

Answer:

should be "d" though i haven't calculated it all exactly

Step-by-step explanation:

A : 85

B : 83

C : 82

D : 81

You might be interested in

Approximate the value of square root 44 to The nearest hundredth

sergiy2304 [10]

Answer:

6.63324958071

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Please help!!!!! It's urgent

Evgesh-ka [11]

2b 2a
----------------- + -----------------
(b+a)^2 (b^2 - a^2)

2b 2a
= ----------------- + -------------------
(b+a)(b+a) (b+a)(b-a)

2b(b - a) + 2a(b + a)
= ------------------------------------
   (b+a)(b+a)(b-a)

2b^2 - 2ab + 2ab + 2a^2
= ---------------------------------------
     (b+a)(b+a)(b-a)

2b^2 + 2a^2
= ------------------------
   (b+a)(b+a)(b-a)

2(b^2 + a^2)
= ------------------------
   (b+a)^2 (b-a)

Answer:

Numerator: 2(b^2 + a^2)
Denominator: (b+a)^2 (b-a)

7 0

4 years ago

What is the slope of the linear equation y = -7x + 7?

Inessa [10]

Answer:

-7

Step-by-step explanation:

y = mx + b is slope-intercept form and m is the slope. In this case m = -7 so the slope is -7.

6 0

3 years ago

HELP AnD SHOW UR WORK please, A recipe calls for 5.25 grams of chocolate. If you have 102.375 grams of chocolate, how many batch

blagie [28]

$[Hello,BrainlyUser]$

Answer:

19.5

Step-by-step explanation:

Given that;

Recipe calls for 5.25 grams of chocolate

Question Ask;

If you have 102.375 grams of chocolate, how many batches,of the recipe can you make?

Note;

102.375 ÷ 5.25 = b

102.375 ÷ 5.25 = Solution

Solve;

$\mathrm{Multiply\:the\:numerator\:and\:denominator\:by:}\:100$

$\frac{10237.5}{525}$

$\mathrm{Write\:the\:problem\:in\:long\:division\:format}$

$\begin{matrix}525\overline{|\smallspace10237.5}\:\:\:\:\:\:\:\:\:\end{matrix}$

$Divide\;1023\;by\;525\;to\;get\;1$

$\begin{matrix}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\emptyspace1\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ 525\overline{|\smallspace10237.5}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\underline{\emptyspace5\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\emptyspace4\emptyspace9\emptyspace8\emptyspace7\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}$

$Divide\;4987\;by\;525\;to\;get\;9$

$\begin{matrix}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\emptyspace19\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ 525\overline{|\smallspace10237.5}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\underline{\emptyspace5\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\emptyspace4\emptyspace9\emptyspace8\emptyspace7\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}$

$\:\:\:\:\:\:\:\:\:\underline{\emptyspace47\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\:\:\:\:\:\:\:\:\:\emptyspace2\emptyspace6\emptyspace2\emptyspace5\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}$

$Divide\;2625\;by\;525\;to\;get\;5$

$\begin{matrix}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\emptyspace19.5\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ 525\overline{|\smallspace10237.5}\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\underline{\emptyspace5\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\ \:\:\:\:\:\:\:\:\:\:\emptyspace4\emptyspace9\emptyspace8\emptyspace7\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}$

$\:\:\:\:\:\:\:\:\:\underline{\emptyspace26\emptyspace2\emptyspace5}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\\:\:\:\:\:\:\:\:\:\emptyspace\emptyspace\emptyspace0\:\:\:\:\:\:\:\:\:\:\:\:\end{matrix}$

$\mathrm{The\:solution\:for\:Long\:Division\:of}\:\frac{102.375}{5.25}\:\mathrm{is}\:19.5$

[CloudBreeze]

5 0

3 years ago

Can someone help me with this??<br><br> thanks

viva [34]

Number of tickets: T.
Number of customers: c
Initially the number of tickets is T0=150, when the group hasn't sold any tickets (c=0). Then the graph must begin with c=0 and T=150. Point=(0,150). Possible options: Graph above to the right and graph below to the left.
They sell the tickets in pack of three tickets per customer c, then each time they sell a pack of three tickets to a customer, the number of tickets is reduced by 3 (-3c). Then the number of tickets, T, the group has left after selling tickets to c customers is:
T=150-3c→T=-3c+150

For T=0→-3c+150=0→150=3c→150/3=c→c=50. The graph must finish with c=50, T=0. Final point=(c,T)=(50,0)

Answer:
The correct graph is above to the right, beginning on vertical axis with T=150 and finishing on horizontal axis with c=50.
The correct equation is T=-3c+150

7 0

3 years ago

Read 2 more answers