5x^2 - (2x - 3)^2 =
5x^2 - ((2x - 3)(2x - 3)) =
5x^2 - (4x^2 - 6x - 6x + 9) =
5x^2 - (4x^2 - 12x + 9) =
5x^2 - 4x^2 + 12x - 9 =
x^2 + 12x - 9 <===
Call the angles of depression D.
then tan(D)=20/30, or I
arctan(tan(D)) = arctan(⅔)
D=33.690. A is the answer
your calculator probably uses tan^-1 rather than arctan
First, we need to get the total area of the rectangular pool.
Area = l * w
Area = 20 ft * 50 ft
Area = 1000 ft^2
Then the deck is 456 ft^2 with the width of 20ft, the same as the rectangular pool.
Area = l * w
456 = l * 20
l = 456 / 20
l = 22.8 ft.
So the walkway is 22.8ft wide.
Evaluate alternatives and select a solution. Hope this helps