What is 1.33333333332 as a fraction

Mathematics

1 answer:

Alika [10]3 years ago

5 0

Answer:

The number 1.33333 can be written using the fraction 133333/100000

Step-by-step explanation:

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On October 15, 2019, Jon purchased and placed in service a used car. The purchase price was $38,000. This was the only business

san4es73 [151]

Answer:

cost recovery deduction = $1520

Step-by-step explanation:

given data

purchase price = $38,000

used the car business = 80%

used the car personal = 20%

solution

cost recovery limit are

cost recovery limit = asset value × statutory % × mid quater convention ..........1

we know car which have 5 year MACRS convention and as per MACRS depreciated 20 % in 1st year

and here this car is use so no 1st year depreciation

so we use MACRS statutory % method

cost recovery limit = $38000 × 5%

cost recovery limit = $1900

we know maximum limit is $3160

so cost of recovery is $1900

cost recovery deduction is

cost recovery deduction = cost recovery limit - personal use

cost recovery deduction = $1900 - ( $1900 × 20% )

cost recovery deduction = $1520

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4 years ago

Kelly brought a pair of sneakers for 35.00 she also brought a pile of different laces. Each set of laces,l, costs 3.00. Write a

amm1812

Answer:

35+3I

Step-by-step explanation:

35+3I

3 0

3 years ago

Read 2 more answers

If a one-sided null hypothesis for a single mean cannot be rejected at a given significance level, then the corresponding two-si

In-s [12.5K]

Answer:

Two-sided null hypothesis (i.e., the same sample size, the same standard deviation, and the same mean) will also be rejected at the same significance level.

Step-by-step explanation:

The decision rule to reject a null hypothesis at α% level of significance is, if the p-value of the test is less than the level of significance then the null hypothesis of the test is rejected. And if p-value of the test is more than the level of significance then the null hypothesis of the test is failed to be rejected.

Now for a two-tailed test the p-value is, $2\times p-value_{(1-tail)}$ , i.e. the p-value is decreased for a two tail test.