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vaieri [72.5K]
4 years ago
7

Harshdeep was playing basketball with his friends with seconds left before the game ended he attempted a 3 point shot the follow

ing equation models the path of the basketball y=-x^2+4x+5 where x is the elapsed time in seconds
Mathematics
1 answer:
vitfil [10]4 years ago
7 0

Answer:

<h2>After two seconds, the ball reached 9 units up.</h2>

Step-by-step explanation:

The given function is

y=-x^{2} +4x+5

The given function models the path of the ball.

The maxium height the ball reached is given by the vertex of this function, which has coordinates V(h,k), where h=-\frac{b}{2a} and k=f(h).

From the equation, we know that a=-1, b=4 and c=5. Replacing these values, we have

h=-\frac{4}{2(-1)}=2

k=f(2)=-(2)^{2} +4(2)+5=-4+8+5=9

Where k determines the height and h the time when the maximum height was reached by the ball.

The maximum height is 9 units.

Therefore, after two seconds, the ball reached 9 units up.

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Find the area of a triangle whose two sides are 18cm and 10cm and the perimeter is 42cm
kobusy [5.1K]

Ur answer will be - A≈69.65cm².  

<u><em>Hope this helps!!</em></u>

5 0
3 years ago
A square has an area of 4 ft^2 what is the lenght of each side
sergiy2304 [10]

area of square = 4ft²

a s area of square = length×lenght

let lenght =x

so area = x²

x²= 4ft²

taking square root

x=2 ftSo lebght of each side is 2 ft.

5 0
3 years ago
Write an equation for the line that passes through (3, 6) and (4, 8).
Snowcat [4.5K]

Answer:

your answer is A: y = 2x

Step-by-step explanation:

4 0
4 years ago
Justine answered 68 questions correctly on a 80-question test.
cestrela7 [59]
For A the answer is 85% correct. Then 15% incorrect. I got the number correct by taking 68 and dividing by 80. To get the number incorrect I took the 15 other questions (80-68) and did 12 divided by 80 to get the 15% incorrect.
5 0
4 years ago
Square ABCD is located on a coordinate plane. The coordinates for three of the vertices are listed below. ~A(2,7) ~C(8,1) ~D(2,1
Vladimir79 [104]

Answer:

B' (16, 14)

Step-by-step explanation:

<em>Whenever we have a dilation with a scale factor b, we get the new point as:</em>

<em>Let original point be (x,y), then the dilation would make it (bx, by).</em>

<em />

There is a diagonal that goes through AC and another through BD. The midpoint of both the diagonal is same. Midpoint formula is:

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

<u>Midpoint of AC:</u>

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\=(\frac{2+8}{2},\frac{7+1}{2})\\=(5,4)

Now let vertex B have coordinates (x,y). <u>Midpoint of BD:</u>

(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})\\=(\frac{x+2}{2},\frac{y+1}{2})

<em>Equate this to the midpoint of AC:</em>

<em>(x+2)/2=5</em>

<em>x+2 = 10</em>

<em>x = 8</em>

<em />

<em>and</em>

(y+1)/2=4

y+1=8

y = 7

Thus, B(8,7)

<em>recalling dilation of scale factor 2 rule we said at the beginning, B' would be twice of each coordinate. Hence B' = (16,14)</em>

7 0
3 years ago
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