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3 years ago

Convert 15/50 to a percent. 0.3% 3.0% 30%

Mathematics

2 answers:

nata0808 [166]3 years ago

5 0

Answer:

30 %

Step-by-step explanation:

Given : $\frac{15}{50}$ .

To find : Convert 15/50 to a percent.

Solution : We have given $\frac{15}{50}$ .

To convert the fraction in to percentage we need to multiply it by 100.

$\frac{15}{50}$ * 100.

15 * 2.

30 %

Therefore, 30 %

denis-greek [22]3 years ago

3 0

30% hope this helped

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Answer:

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nlexa [21]

Answer:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

a. 11.070

And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

For this case we want to test:

H0: Absenteeism is distributed evenly throughout the week

H1: Absenteeism is NOT distributed evenly throughout the week

We have the following data:

Monday Tuesday Wednesday Thursday Friday Saturday Total

12 9 11 10 9 9 60

The level of significance assumed for this case is $\alpha=0.05$

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

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now we can calculate the statistic:

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Now we can calculate the degrees of freedom (We know that we have 6 categories since we have information for 6 different days) for the statistic given by:

$df=categor-1=6-1=5$

The critical value can be founded with the following Excel formula:

=CHISQ.INV(1-0.05,5)

And we got $\chi^2_{critc}= 11.0705$

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And since our calculated value is lower than the critical we FAIL to reject the null hypothesis at 5% of significance

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