<span>Let the width of the rectangular plot of land be 'x' yards.
Given that the length of the rectangular plot of land is 10 yards more than its width.
So, width of the rectangular plot of land = (x + 10) yards.
Also given that the area of the rectangular plot of land is 600 square yards.
We know that, area of a rectangle = length * width
That is, (x+10) * x = 600
x^2 + 10x = 600
x^2 + 10x - 600 = 0
x^2 + 30x - 20x -600 = 0
x(x + 30) - 20(x + 30) = 0
(x +30)(x -20) =0
Therefore, either (x + 30) = 0 or (x - 20) = 0
If x + 30 = 0, then x = -30 and
If x - 20 = 0, then x = 20
Since 'x' represents the width of a rectangular plot of land it cannot be negative.
Therefore,
width of the rectangular plot of land = 20 yards
length of the rectangular plot of land= x + 10 = 30 yards</span>
Answer:
2) 45
3) 25
4) 50%
5) 33.3%
6) 17.6
7) 500
8) 35%
9) 60
10) 87.5%
11) 2.64
12) 25%
13) 5.7
14) 85%
16) 75%
Step-by-step explanation:
2) 9 = 20% of x
9 * 5 = 45
3) 8% of x = 2
12.5 * 2 = 25
4) 39 = x(78)
39/78 = 1/2 = 50%
5) x(36) = 12
12/36 = 1/3 = 33.3...%
6) x = 0.8(22)
22/10 = 2.2
2.2* 8 = 16 + 1.6 = 17.6
7) 55 = 0.11(x)
55/11 = 5
5 * 100 = 500
8) 7/20 = 35/100 = 35%
9) 27 = 0.45(x)
27/45 = 3/5
3/5 * 100 = 300/5 = 60
10) . 49/56 = 7/8 = 0.875 = 87.5%
11) 6/100 = 0.06
0.06 * 44 = 2.64
12) 48/192 = 6/24 = 1/4 = 25%
13) 95/100 = 0.95
0.95 * 6 = 5.40 + 0.3 = 5.7
14) 68/80 = 34/40 = 17/20 = 85%
16) 108/144 = 9/12 = 0.75 = 75%
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Answer: don't know sorry
Step-by-step explanation:
Answer:
The graph in the attached figure
Step-by-step explanation:
we have
----> equation A
----> equation B
Solve the system by graphing
Remember that the solution of the system is the intersection point both graphs
Using a graphing tool
The intersection point is (1,5)
see the attached figure
therefore
The solution of the system is the point (1,5)
