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dexar [7]
2 years ago
5

Find the equation of the line containing the point (3, 3) and parallel to the line

Mathematics
1 answer:
DIA [1.3K]2 years ago
3 0

Answer:

y = 2x - 3

Step-by-step explanation:

Parallel lines have the same slope

only the constant changes

y = 2x + b

To find "b"

Plug in point (3, 3)

3 = 2(3) + b

3 = 6 + b

Subtract 6 from both sides

-3 = b

The equation for the parallel line is

y = 2x - 3

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Find the equation of the line that is perpendicular to LaTeX: y=-\frac{1}{5}x+3y = − 1 5 x + 3 and goes through the point (4, -3
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Answer:

y=5x-23

Step-by-step explanation:

step 1

Find the slope of the line that is perpendicular to the given line

we have

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The slope of the given line is

m=-\frac{1}{5}

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal

therefore

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step 2

Find the equation of the line in slope intercept form

y=mx+b

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