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ohaa [14]
3 years ago
8

HURRY!!!! Determine the coordinates of the point on the unit circle corresponding to the given central angle. If necessary, roun

d your results to the nearest hundredth. 270 degrees a. (1, 0) c. (0, -1) b. (0, 1) d. (-1, 0)
Mathematics
1 answer:
nadezda [96]3 years ago
3 0

Answer:

The answer is c. (0,-1)

Step-by-step explanation:

So the unit circle is derived from a right triangle.

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Cos²x + sin^2x/cscx-cot^2x
Anna [14]

Answer:

1.

Step-by-step explanation:

I am assuming you want to simplify this.

cos^2 x + sin^2 x = 1 and

csc^2 x = 1 + cot^2 x   so  csc^2x - cot^2 x = 1

So the answer is 1/1 = 1.

5 0
3 years ago
Shoes cost $80 they are discounted at 40% off.The tax is 6.75%.What is the final cost of the shoes.
Brilliant_brown [7]
You have to turn the percent into a decimal to do the math. 

80 * .40 = 32 (That's the discount.) Now we subtract the orginal price from this.

80 - 32 = 48

Now we need to find the tax value.

48 (our new price) *  .0675 = $3.24

Add this back onto the price to get our final price.

3.24 + 48 = $51.24 
8 0
3 years ago
Can someone explain how u get the answer
Airida [17]

Answer:

yes

Step-by-step explanation:

i cant see da pic

6 0
3 years ago
Read 2 more answers
I need to solve for X Y and Z please and thank you
erastovalidia [21]

9514 1404 393

Answer:

  • x = 5
  • y = 30
  • z = 8

Step-by-step explanation:

The rhombus has several relevant properties.

  • The sides are all the same length
  • Diagonals are perpendicular bisectors of each other
  • Diagonals divide the rhombus into congruent triangles

The last of these relations can be used to find x:

  7x° = 35°

  x = 35°/7° = 5

The second of the relations can be used to find y:

  3y° = 90°

  y = 90°/3° = 30

The first of the relations can be used to find z:

  10z -8 = 5z +32

  5z = 40 . . . . . . . . . add 8-5z

  z = 40/5 = 8

4 0
3 years ago
Someone get me the answers ASAP!! thank you
Virty [35]
This relies on the distance formula like number two, which you answered correctly.

I think it's helpful to draw this out. I made a digital drawing on GeoGebra (free) and connected the vertices. Now, to find the area, we need the side lengths to start. This program actually gives you the side lengths as well, but pretending we don't already have that, you can plug in each vertex into the distance formula.

a =  \sqrt{(-4-3)^{2}+ (2-2)^{2}} = 7

b =  \sqrt{(3-3)^{2}+(2-(-5))^{2}} = 7

c =  \sqrt{(3-(-4))^{2}+(-5-(-2))^{2}} =  \sqrt{58}

d =  \sqrt{(-4-(-4))^{2}+(2-(-2))^{2}} = 4

So, unfortunately, we don't have a regular polygon, so this isn't simply length times width. But we can easily cut this into a rectangle and a triangle, whose areas are much easier to find (see second image).

The area, A, of a triangle is \frac{1}{2} B * h and the area of a rectangle is simply l * w. So the base of our triangle is 7 units, and the height is 3 units, so the area is 10.5 units squared. The length of our rectangle is 7 units, and the width is 4 units, so the area is 28 units squared.

A = A_{triangle} + A_{rectangle} = 10 \frac{1}{2}+28 = 38\frac{1}{2} units squared.



I would like to clarify that you do not actually need to find all those distances for this problem. Once it's drawn out, it's fairly easy to tell.

7 0
4 years ago
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