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Margaret [11]
3 years ago
9

Which of the following is a name for the ray drawn below

Mathematics
2 answers:
wlad13 [49]3 years ago
4 0
CR –> is the name of the ray
Kaylis [27]3 years ago
3 0

Answer:

CR

Step-by-step explanation:

Thinking process:

This is a question of vectors.

There are a few things to remember about vectors:

A point AB is denoted by the notation AB, starting from the point of origin to the end point.

In the answers, CR satisfies the question

AC is the opposite, so it is rejected as the direction is not the same as the arrow.

Similarly, RC is rejected

AR is the point somewhere on the line not the origin.

This leaves us with CR as the correct answer.

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MZHGF = 16x +4, mZEGF = 110°, and mZHGE= 3x + 11. Find x.
Len [333]

Answer:

x=9

Step-by-step explanation:

I hope this helps you

16x+4=110+3x+11

13x=117

x=9

3 0
2 years ago
What is 52% of 25? plzz helppp
Sonbull [250]

Answer: its 13

Step-by- 52 percent *25 =

(52:100)*25 =

(52*25):100 =

1300:100 = 13

step explanation:

5 0
2 years ago
Read 2 more answers
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
3 years ago
Im having some trouble with this and have no idea
AlladinOne [14]

Answer:

Step-by-step explanation:

x+10=0

x=-10

so vertex is (-10,-105)

7 0
2 years ago
7. Find the range of the function f(x) = 4x – 1 for the domain {-1, 0.1.2.3). (I point)
Alex_Xolod [135]

Answer: {{ -5 , -1 , 3 , 7 , 11 } }

Step-by-step explanation:

Given :

f(x) = 4x - 1

domain = { -1 , 0 , 1 , 2 , 3 }

To find the range , we will substitute the domain as the value of x into the function given , that is

when x = - 1

f(x) = 4 (-1) - 1

f(x) = -5

when x = 0

f(x) = -1

when x = 1

f(x) = 4(1) - 1

f(x) = 3

When x = 2

f(x) = 7

when x = 3

f(x) = 11

Therefore: the range = { -5 , -1 , 3 , 7 , 11 }

3 0
3 years ago
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