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adoni [48]
3 years ago
7

Stan says that the least common multiple of 6 and 8

Mathematics
1 answer:
Kazeer [188]3 years ago
5 0
Then the lest multiple of 6 and 8 are 5 and 7 duh
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X×9=y, y-70=11 , y=?​
solmaris [256]

Answer:

y=81

Step-by-step explanation:

x=9 and y=81

y-70=11 (add 70 onto 11)

y=81

5 0
3 years ago
Read 2 more answers
WILL GIVE BEST RESPONSE
tino4ka555 [31]
We will use demonstration of recurrences<span>1) for n=1, 10= 5*1(1+1)=5*2=10, it is just
2) assume that the equation </span>10 + 30 + 60 + ... + 10n = 5n(n + 1) is true, <span>for all positive integers n>=1
</span>3) let's show that the equation<span> is also true for n+1, n>=1
</span><span>10 + 30 + 60 + ... + 10(n+1) = 5(n+1)(n + 2)
</span>let be N=n+1, N is integer because of n+1, so we have
<span>10 + 30 + 60 + ... + 10N = 5N(N+1), it is true according 2)
</span>so the equation<span> is also true for n+1, 
</span>finally, 10 + 30 + 60 + ... + 10n = 5n(n + 1) is always true for all positive integers n.
<span>
</span>
4 0
3 years ago
Rename 5/6 and 14/15 using the least common denominator.
baherus [9]

Answer:

\frac{25}{30}~and~\frac{28}{30}

  • Multiply 5 by 5 to get your first parameter.

5 * 5 = 25

  • Multiply 6 by 5 to get the denominator, or your second parameter.

5 * 6 = 30

  • For the second fraction, \frac{14}{15}, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.

14 * 2 = 28

  • Now, multiply 15 by 2

15 * 2 = 30

  • The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.

25~and~30 -- > \frac{25}{30}

28~and~30-- > \frac{28}{30}

________________________________________________________

Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>

________________________________________________________

<h3>What have we learned?</h3>

We learned how to efficiently make fractions' deominators match.

Questions related to this topic? Ask me in the comments box, please!

8 0
3 years ago
What does 5 cubed equal?
storchak [24]

Answer:

125

Step-by-step explanation:

it is the multiflication of 5 by itself 3 times (5×5×5=125)

6 0
2 years ago
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How do you do factorise this problem 9x^2 + 3x^3
Alenkinab [10]

Answer:

3x^{2} (3 +x)

Step-by-step explanation:

take the 3x^2 common

4 0
3 years ago
Read 2 more answers
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