Answer:
20ft²
Step-by-step explanation:
Answer: C, the answer would be 8
Explanation: simplify by breaking the radican up into a product of known factors, which would leave you with 8
Hope this helps!
Answer:
![r\approx0.03\text{ or about $3\%$}](https://tex.z-dn.net/?f=r%5Capprox0.03%5Ctext%7B%20or%20about%20%243%5C%25%24%7D)
Step-by-step explanation:
The standard compound interest formula is given by:
![\displaystyle A=P(1+\frac{r}{n})^{nt}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20A%3DP%281%2B%5Cfrac%7Br%7D%7Bn%7D%29%5E%7Bnt%7D)
Where A is the amount afterwards, P is the principal, r is the rate, n is the times compounded per year, and t is the number of years.
Since we are compounding annually, n=1. Therefore:
![\displaystyle A = P (1+r)^{t}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%20A%20%3D%20P%20%281%2Br%29%5E%7Bt%7D)
Lester wants to invest $10,000. So, P=10,000.
He wants to earn $1000 interest. Therefore, our final amount should be 11000. So, A=11000.
And our timeframe is 3.3 years. So, t=3.3. Substituting these values, we get:
![11000=10000(1+r)^{3.3}](https://tex.z-dn.net/?f=11000%3D10000%281%2Br%29%5E%7B3.3%7D)
Let’s solve for our rate r.
Divide both sides by 10000:
![1.1=(1+r)^{3.3}](https://tex.z-dn.net/?f=1.1%3D%281%2Br%29%5E%7B3.3%7D)
We can raise both sides to 1/3.3. So:
![\displaystyle (1.1)^\frac{1}{3.3}=((1+r)^{3.3})^\frac{1}{3.3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%281.1%29%5E%5Cfrac%7B1%7D%7B3.3%7D%3D%28%281%2Br%29%5E%7B3.3%7D%29%5E%5Cfrac%7B1%7D%7B3.3%7D)
The right side will cancel:
![\displaystyle r+1=(1.1)^\frac{1}{3.3}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%2B1%3D%281.1%29%5E%5Cfrac%7B1%7D%7B3.3%7D)
So:
![\displaystyle r=(1.1)^\frac{1}{3.3}-1](https://tex.z-dn.net/?f=%5Cdisplaystyle%20r%3D%281.1%29%5E%5Cfrac%7B1%7D%7B3.3%7D-1)
Use a calculator:
![r\approx0.03](https://tex.z-dn.net/?f=r%5Capprox0.03)
So, the annual rate of interest needs to be about 0.03 or 3% in order for Lester to earn his interest.