-- Find how much 'y' changes from the first point to the second one.
-- Find how much 'x' changes from the first point to the second one.
-- The slope of the line going from the first point to the second one is
(change in 'y') / (change in 'x') .
Given:
Current revenue = $6000
<span>R(f)= -100f^2 + 400f + 6000
where f is a whole number of $5 fee increases
We are told to find f, when R(f) </span><span>< 6000
Since </span>R(f)= -100f^2+400f+6000
R(f) < 6000 ⇒ -100f^2+400f+6000 < 6000
Subtract 6000 from both sides
-100f^2 + 400f + 6000 - 6000 < 6000 - 6000
-100f^2 + 400f < 0
⇒ 400f - 100f^2 < 0
Divide the equation by 100
400f/100 - 100f^2/100 < 0/100
4f - f^2 < 0
Add f^2 to both sides of the equation
4f - f^2 + f^2 < 0 + f^2
4f < f^2
Divide both sides by f
4f/f < (f^2)/f
4 < f
⇒ f > 4
⇒ f ≥ 5
Therefore, <span> for 5 or more numbers of $5 fee increases, the revenue from fees will actually be less than its current value.</span>
The linear function g which has a rate of change of -16 and initial value 600 is; g = -16x + 600.
<h3>What is the linear function which is as described?</h3>
It follows from the task content that the linear expression which is as described by the given verbal description is to be determined.
Since the standard slope-intercept form of a linear function is as given; f(x) = ax + b.
Where, a = slope (rate of change) and b = y-intercept (initial value).
Therefore, the required linear function which is as described is;
g = -16x + 600
Read more on linear functions;
brainly.com/question/15602982
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Answer:
Step-by-step explanation:
Given : the seasons graph below shows the average daily temperature over the period of a year.
To Find: explain how each labeled section of the graph relates to the four seasons
Solution:
Considering the graph
"A"is representing Winter (Jan - Feb) when the temperature is the lowest.
"B" is representing Spring when the temperature is increasing.
"C"is representing Summer when the average temperature increase, then decrease.
"D" is representing Autumn when the average temperature is decreasing.
