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Agata [3.3K]
2 years ago
15

For the past week, your restaurant revenue was $28,675 and your food cost was $9,274. Calculate your gråss margi

Mathematics
1 answer:
Len [333]2 years ago
3 0

Answer: b) 68%

Step-by-step explanation:

Gross margin is used to calculate the amount left of revenue after the costs of goods sold is accounted for.

The formula is:

= (Revenue - Cost) / Revenue

= (28,675 - 9,274) / 28,675

= 0.67658

= 68%

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Since top 3 racers recognized with the same award, answer is 3/12 or 1/4 or .25
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Which statement could the expression n + 1 represent? one point greater than the last test grade the difference of Gina's score
sukhopar [10]

Answer:

A. One point greater than the last test grade.

Step-by-step explanation:

One point greater than the last test grade can be written as an expression:n + 1

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n - 1

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On a long distance bike trip Annike started at 7 a.m and her average speed was 11 miles per hour and Celia travels 14 miles per
Troyanec [42]

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equation: 11×14=154 14×11=154

Step-by-step explanation:

counting by 11:

11 22 33 44 55 66 77 88 99 110 121 132 143 <em><u>154</u></em>

11 × 14 = 154

counting by 14:

14 28 42 56 70 84 98 112 126 140 <em><u>154</u></em>

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8 0
3 years ago
The computers of nine engineers at a certain company are to be replaced. Four of the engineers have selected laptops and the oth
Gala2k [10]

Answer:

(a) There are 70 different ways set up 4 computers out of 8.

(b) The probability that exactly three of the selected computers are desktops is 0.305.

(c) The probability that at least three of the selected computers are desktops is 0.401.

Step-by-step explanation:

Of the 9 new computers 4 are laptops and 5 are desktop.

Let X = a laptop is selected and Y = a desktop is selected.

The probability of selecting a laptop is = P(Laptop) = p_{X} = \frac{4}{9}

The probability of selecting a desktop is = P(Desktop) = p_{Y} = \frac{5}{9}

Then both X and Y follows Binomial distribution.

X\sim Bin(9, \frac{4}{9})\\ Y\sim Bin(9, \frac{5}{9})

The probability function of a binomial distribution is:

P(U=k)={n\choose k}\times(p)^{k}\times (1-p)^{n-k}

(a)

Combination is used to determine the number of ways to select <em>k</em> objects from <em>n</em> distinct objects without replacement.

It is denotes as: {n\choose k}=\frac{n!}{k!(n-k)!}

In this case 4 computers are to selected of 8 to be set up. Since there cannot be replacement, i.e. we cannot set up one computer twice or thrice, use combinations to determine the number of ways to set up 4 computers of 8.

The number of ways to set up 4 computers of 8 is:

{8\choose 4}=\frac{8!}{4!(8-4)!}\\=\frac{8!}{4!\times 4!} \\=70

Thus, there are 70 different ways set up 4 computers out of 8.

(b)

It is provided that 4 computers are randomly selected.

Compute the probability that exactly 3 of the 4 computers selected are desktops as follows:

P(Y=3)={4\choose 3}\times(\frac{5}{9})^{3}\times (1-\frac{5}{9})^{4-3}\\=4\times\frac{125}{729}\times\frac{4}{9}\\  =0.304832\\\approx0.305

Thus, the probability that exactly three of the selected computers are desktops is 0.305.

(c)

Compute the probability that of the 4 computers selected at least 3 are desktops as follows:

P(Y\geq 3)=1-P(Y

Thus, the probability that at least three of the selected computers are desktops is 0.401.

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