<span>At the end of meiosis II, the DNA in each of the four new cells compared to the DNA from the original cell is half as much and genetically different from the original. Meiosis is a part of cell division that results in the reduction of chromosome number by half in daughter cells. So, all daughter cells will have as half as much the original cell have. Nonetheless, during meiosis, the exchange of genetic material between homologous chromosomes occur. So, all daughter cells are genetically different from the original cell.</span>
Answer:
C Enzymes read the DNA code and build a new DNA molecule from scratch
You need to show a picture I can’t help you if you don’t show it
This is due to the fact that only homologous chromosomes would have identical genes located at identical sites on those chromosomes. Otherwise, there would be no connection between the alleles of various genes.
Although the genes and loci of the two members of the homologous pair are similar, the alleles may vary.For instance, both allele possess the genes responsible for the attribute of eye colour. While the one has alleles for the blue-eye trait, other has alleles for the brown-eye trait. The homologous chromosomes are said to be heterozygous in this instance since the alleles are different.
On the other hand, when both alleles for a gene that codes for the blue-eye phenotype are present, it is said to be homozygous.
To learn more about homologous chromosomes click here
brainly.com/question/27258467
#SPJ4
Answer:
A. His mitochondria lack the transport protein that moves pyruvate across the outer mitochondrial membrane.
Explanation:
Pyruvate is from the breakdown of carbohydrates such as glucose through glycolysis. Glucose enters the cytosol through specific transporters (the GLUT family) and is processed by one of several pathways depending on cellular requirements. Glycolysis occurs in the cytosol and produces a limited amount of ATP, but the end product is two 3-carbon molecules of pyruvate, which maybe diverted again into many pathways depending on the requirements of the cell. In aerobic conditions, pyruvate is primarily transported into the mitochondrial matrix and converted to acetyl-coenzyme A (acetyl-CoA) and carbon dioxide by the pyruvate dehydrogenase complex (PDC).
Initially it was proposed that pyruvate was able to cross the membrane in its undissociated (acid) form but evaluation of its biochemical properties show that it is largely in its ionic form within the cell and should therefore require a transporter.
Transport of pyruvate across the outer mitochondrial membrane appears to be easily accomplished via large non-selective channels such as voltage-dependent anion channels/porin, which enable passive diffusion. Indeed, deficiencies in these channels have been suggested to block pyruvate metabolism