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3 years ago

Is (3,2) a solution of -8x-2y<6

Mathematics

2 answers:

erik [133]3 years ago

8 0

-8(3) -2(2) < 6
-24 - (-4) < 6
-28 < 6

-28 is less than 6

UkoKoshka [18]3 years ago

4 0

Answer:

yes

Step-by-step explanation:

to determine if the point is a solution substitute the x and y values into the inequality and check validity

(- 8 × 3 ) - (2 × 2) = - 24 - 4 = - 28 < - 6 ← True

hence (3, 2) is a solution of the inequality

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The rectangle graphed has a length of 5 and a width of 4 how does the perimeter change when the width is decreased by half

Nuetrik [128]

Answer:

It decreases by 4 units

Step-by-step explanation:

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allochka39001 [22]

Answer:

y=3x-2..... i

x-y=4...... ii

x-4=y

Substituting the value of y in equation i,

x-4=3x-2

2-4=3x-x

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x=-1.

From ii,

-1-4=y

y=-5.

x=-1, y=-5

Step-by-step explanation:

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4 years ago

Triangle A C B is shown. Angle A C B is a right angle. Altitude h is drawn from point C to point D on side A B, forming a right

monitta

Answer:

Answer B.) $\sqrt[2]{70}$

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3 years ago

Read 2 more answers

WILL GIVE BRAINLIEST!!!!! Given the equation y = x – 2, you substitute 3 for y. Check all true statements below.

Sonja [21]

Answer:

y=x-2

a. 3=x-2

b. this isn't wrong??

c. 3=x-2

d. add 2 to both side so taht x is on its own so 5=x

e. yes

5 0

3 years ago

Read 2 more answers

Erik and Caleb were trying to solve the equation: 0=(3x+2)(x-4) Erik said, "The right-hand side is factored, so I'll use the zer

Mumz [18]

Answer:

C) Both

Step-by-step explanation:

The given equation is:

$0=(3x+2)(x-4)$

To solve the given equation, we can use the Zero Product Property according to which if the product <em>A.B = 0</em>, then either A = 0 OR B = 0.

Using this property:

$(3x+2) = 0 \Rightarrow \bold{x = -\frac{2}{3}}\\(x-4) = 0 \Rightarrow \bold{x = 4}$

So, Erik's solution strategy would work.

Now, let us discuss about Caleb's solution strategy:

Multiply $(3x+2)(x-4)$ i.e. $3x^2-12x+2x-8$ = $3x^2-10x-8$

So, the equation becomes:

$0=3x^2-10x-8$

Comparing this equation to standard quadratic equation:

$ax^2+bx+c=0$

a = 3, b = -10, c = -8

So, this can be solved using the quadratic formula.

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{-(-10)\pm\sqrt{(-10)^2-4\times3 \times (-8)}}{2\times 3}\\x=\dfrac{-(-10)\pm\sqrt{196}}{6}\\x=\dfrac{10\pm14}{6} \\\Rightarrow x= 4, -\dfrac{2}{3}$

The answer is same from both the approaches.

So, the correct answer is:

C) Both

3 0

3 years ago