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MrMuchimi
3 years ago
14

Choose the equation below that represents the line passing through the point (2, -5) with a slope of -3.

Mathematics
1 answer:
mash [69]3 years ago
4 0
The point-slope form: y-y_0=m(x-x_0)

m=-3;\ (2;-5)\to x_0=2;\ y_0=-5

subtitute

y-(-5)=-3(x-2)\\\\y+5=-3x+6\ \ \ \ \ |subtract\ 5\ from\ both\ sides\\\\\boxed{y=-3x+1}
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Step-by-step explanation:

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D' (6 , 3)

E' (-9 , 6)

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3 years ago
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|10| > |-7|

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7 0
3 years ago
Read 2 more answers
What is the equation of the line that passes through the point (-5,5)and has a slope of -1
erastova [34]

Answer:

<h2>           y = - x  </h2>

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = -1

(-5, 5)    ⇒   x₀ = -5,  y₀ = 5

The point-slope form of the equation:

y - 5 = -1(x + 5)

So:

y - 5 = -x - 5         {add 5 to both sides}

y = -x             ←  the slope-intercept form of the equation

3 0
3 years ago
Is line m: -x+2y=6 parallel, perpendicular, or neither parallel nor perpendicular to line n: y=-2x+6?
Serhud [2]
Make them both equal to y

y=-2x+6

2y=x+6 y=1/2x+3

These are perpendicular since ones slope is -2 and the other is the opposite, 1/2.
7 0
3 years ago
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