Choose the equation below that represents the line passing through the point (2, -5) with a slope of -3.

1 answer:

4 0

The point-slope form: $y-y_0=m(x-x_0)$

$m=-3;\ (2;-5)\to x_0=2;\ y_0=-5$

subtitute

$y-(-5)=-3(x-2)\\\\y+5=-3x+6\ \ \ \ \ |subtract\ 5\ from\ both\ sides\\\\\boxed{y=-3x+1}$

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a group of students help a fundraiser last year and raised $950 for charity . This year, they raised $1,045. What is the percent

MakcuM [25]

1045-950 = 95

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4 0

3 years ago

Read 2 more answers

Find each absolute value | 4+2i | | 5-i | | -3i |

galina1969 [7]

How to get answer for number 1: | 4+2i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=4,\:b=2\\=\sqrt{4^2+2^2}\\Refine\\=\sqrt{20}\\\sqrt{20}=2\sqrt{5}\\=2\sqrt{5}$

How to get answer for number 2: | 5-i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=5,\:b=-1\\=\sqrt{5^2+\left(-1\right)^2}\\=\sqrt{26}$

Number 3 how to get answer: | -3i |

$\left|a+bi\right|\:=\sqrt{\left(a+bi\right)\left(a-bi\right)}=\sqrt{a^2+b^2}\\\mathrm{With\:}a=0,\:b=-3\\=\sqrt{0^2+\left(-3\right)^2}\\Refine\\=\sqrt{9}\\\sqrt{9}\\\mathrm{Factor\:the\:number:\:}\:9=3^2\\=\sqrt{3^2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a^n}=a\\\sqrt{3^2}=3\\= 3$