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3 years ago

6- 9 L- 5 -5 4 -3 3 у X :9 Howa urah puy

Mathematics

1 answer:

VladimirAG [237]3 years ago

5 0

Answer:

1028284757574622719193495756657472911001202838576 770643j 473745637 1919 84 65727281910e445966 tu 5737272532

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Kim is trying to lose weight. She is currently 186 lbs. Her goal is to lose 2.2 lbs. a week until she is down to 153 lbs. How ma

kherson [118]

15 weeks it will take 2.2x15 is 33-186=153

6 0

2 years ago

How many hours is 529 miles

anzhelika [568]

I need more information than that, to answer this question. :/

6 0

3 years ago

There were 306 students in the cafeteria. After some went outside, there were 249 students left in the cafeteria. How many stude

AysviL [449]

Answer:

The equation to solve the problem is

306 = 249 + x

x = 306 - 249

Hence:

57 students went outside

Step-by-step explanation:

Let the number of students outside be represented by x

Hence:

Number of students in the cafeteria = Number of students inside - Number of students who went outside

We are told:

There were 306 students in the cafeteria. After some went outside, there were 249 students left in the cafeteria.

The equation to solve the problem is given as:

306 = 249 + x

x = 306 - 249

Hence:

x = 57

57 students went outside

4 0

3 years ago

PLEASE HELP ASAP

Crank

Option D: $f(x)=-2(x+2)(x-4)$ is the function

Explanation:

Let the general form of quadratic equation be $y=a x^{2}+b x+c$

The function passes through the intercepts $(-2,0)$ and $(4,0)$ and also passes though the point $(-1,10)$

Substituting the points $(-2,0)$ , $(4,0)$ and $(-1,10)$ in the equation $y=a x^{2}+b x+c$ , we get,

$4a -2b+c=0$ -----------(1)

$16a +4b+c=0$ ----------(2)

$a-b+c=10$ -----------(3)

Subtracting (1) and (2), we get,

$\ \ 4a -2b+c=0\\ 16a +4b+c=0\\\---------\\ \ \ -12a-6b=0$ -----------(4)

Subtracting (2) and (3), we get,

$16a +4b+c=0\\\ \ a \ \ - \ \ b \ +c=10\\---------\\15a+5b=-10$ ------------(5)

Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,

$-60a-30b=0\\\ 90a+30b=-60\\--------\\30a=-60\\\ \ a=-2$

Thus, the value of a is $a=-2$

Substituting $a=-2$ in equation (4), we get,

$\begin{aligned}-12 a+6 b &=0 \\-12(-2)-6 b &=0 \\ 24-6 b &=0 \\ 24 &=6 b \\ 4 &=b \end{aligned}$

Thus, the value of b is $b=4$

Now, substituting the value of a and b in equation (1), we have,

$\begin{aligned} 4 a-2 b+c &=0 \\ 4(-2)-2(4)+c &=0 \\-8-8+c &=0 \\ c &=16 \end{aligned}$

Thus, the value of c is $c=16$

Now, substituting the value of a,b and c in the general formula $y=a x^{2}+b x+c$ , we get,

$y=-2x^{2} +4x+16$

Taking out the common term as -2 we get,

$y=-2(x^{2} -2x-8)$

Factoring , we get,

$y=-2(x+2)(x-4)$

Thus, the function is $f(x)=-2(x+2)(x-4)$

7 0

3 years ago

What is the area of ruth's mural?

pentagon [3]

Answer:

Step-by-step explanation:

Comment

The shape consists of a rectangle on the bottom and a trapezoid on the top.

Rectangle

A rectangle has a very simple Area formula. It is Area = L*W. In this case the L = 14 m and is horizontal. The width is at right angles to the length and is marked as 3.

Area = L * w

L = 14

w = 3

Area = 14 * 3 = 42 m^2

Trapezoid

The trapezoid is a bit more complicated and some things have to be found. First of all b1 is the first base of the trapezoid. It is parallel to and equal to the Length of the rectangle. b2 is marked 10 meters. The height is just a bit more complicated. The total height of the figure is 8 m. You can't count the 3 m of the rectangle as part of the height because b1 comes only to the top of the rectangle. The height is 8 - 3 = 5

Area = 1/2(b1 + b2)*h/2

b1 = 14

b2 = 10

h = 8 - 3 = 5

Area = 1/2 ( 14 + 10) * 5 / 2

Area = 1/2 (24)*5

Area = 12 * 5

Area = <u> 60 m^2</u>

Total Area 102 m^2

8 0

2 years ago