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posledela
4 years ago
12

A group of workers applied 10.0 networks of force to move a crate 20.0 meter. Calculate the work

Physics
1 answer:
olga2289 [7]4 years ago
4 0

The work done is 200 J

Explanation:

The work done by a force applied to move an object is given by:

W= F d cos \theta

where

F is the magnitude of the force

d is the displacement of the object

\theta is the angle between the direction of the force and of the displacement

In this problem, assuming that the force applied by the workers is parallel to the direction of motion of the crate, we have:

F = 10.0 N

d = 20.0 m

\theta=0^{\circ}

Therefore, the work done is:

W=(10.0)(20.0)(cos 0)=200 J

Learn more about work here:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

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riadik2000 [5.3K]

Answer:

A) Both soap products were more effective than the hand sanitizer

Explanation:

Both soap products together are more than the hand sanitizer

3 0
3 years ago
An electron (mass 9 × 10-31 kg) is traveling at a speed of 0.92 in an electron accelerator. An electric force of 1.4 × 10-13 N i
pogonyaev

Given Information:

Mass of electron = m = 9x10⁻³¹ kg

initial speed of electron = v₁ = 0.92c

Force = F =  1.4x10⁻¹³ J

Distance = d = 3 m

Required Information:

Final speed of electron = v₂ = ?

Answer:

Final speed of electron = v₂ = 2.974x10⁸ m/s

Explanation:

As we know from the conservation of energy,

E₂ - E₁ = W

E₂ = E₁ + W

Where E₂ is the final energy of electron and E₁ is the initial energy of electron

The above equation can be written in the form of particle energy

γ₂mc² = γ₁mc² + W

where γ₁ and γ₂ are given by

γ₁ = 1/√1 - (v₁/c)²

γ₂ = 1/√1 - (v₂/c)²

First calculate γ₁

γ₁ = 1/√1 - (0.92c/c)²

γ₁ = 2.55 m

Now calculate γ₂

γ₂ = (γ₁mc² + W)/mc²

First we need to find the work done

W = F*d

W = 1.4x10⁻¹³*3

W = 4.2x10⁻¹³ J

so γ₂ is

γ₂ = (2.55*9x10⁻³¹*(3x10⁸)² + 4.2x10⁻¹³)/9x10⁻³¹*(3x10⁸)²

γ₂ = 7.73

Now we can find the new speed of the electron

γ₂ = 1/√1 - (v₂/c)²

Re-arranging the above equation results in

v₂ = c*√(1 - 1/γ₂²)

v₂ = 3x10⁸*√(1 - 1/7.73²)

v₂ = 2.974x10⁸ m/s

4 0
3 years ago
A band director instructs students to play a pitch louder. How will the sound wave change when the band plays the same pitch lou
ZanzabumX [31]

Answer:

The amplitude of the sound wave will increase.

Explanation:

3 0
4 years ago
Read 2 more answers
While rowing in a race, John uses his arms to exert a force of 155 N per stroke
Basile [38]

Answer:

Workdone = 2906.25J

Explanation:

Given the following data;

Force, F = 155

Distance, d = 0.75

Stroke, s = 25

Mathematically, work done is given by the formula;

Work done = force * distance * stroke

W = F * d * s

Where,

W is the work done

F represents the force acting on a body.

d represents the distance covered by the body.

s is the number of strokes.

Substituting into the equation, we have;

Workdone = 155*0.75*25

Workdone = 2906.25J

6 0
3 years ago
I Need Assistance....
Anna007 [38]
Area of triangle, ECD
Area, A= 60 square inches
Base, b= 12in
Height, h=?

Note that Area of a triangle = 1/2×b×h
Substitute the values: 60 = 1/2×12×h
60 = 6h
h = 10in

The height is 10in.



Coincidentally, the height of the triangle is also the side of the square.
So side of square, L = 10in

Area of a square = L^2 or Side × Side
Area = 10 × 10
Area = 100 square inches.



The area of the trapezoid = area of square + area of triangle
The are of trapezoid = 100 + 60 inches squared = 160inches squared.
7 0
3 years ago
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