Ask question

Ask question

All categories

4 years ago

8

A rabbit hops through a vegetable garden. He first hops 2 m south, then 4 m west, then 3 m south, and finally 1 m east. What dis

tance did the rabbit travel? What is his displacement?

1 answer:

Semenov [28]4 years ago

7 0

Answer:

Distance = 10m

Imagine a triangle

Length = 4 - 1 = 3

Height = 2 + 2 =4

Hypothenuse = Displacement

Displacement = 5

You might be interested in

A man jumps horizontally from the top of a building that is 20.0m high, and hopes to reach a swimming pool that is at the bottom

Oliga [24]

Answer:

5 m/s

Explanation:

Given that the hight of the building, h= 20.0 m

The horizontal distance of the swimming pool from the building, d=10 m

As the man jumps horizontally, so the vertical velocity at the time of jumping is 0.

Let s be the initial horizontal velocity of the man at the time of jumping.

As the gravitational force always acts in the vertical direction, so, it does not change the horizontal speed.

So, the horizontal velocity, s, remains constant throughout the motion.

If t be the time of flight, then $s=10/t \cdots(i)$

Now, applying the equation of motion in the vertical direction,

$s=ut+\frac 1 2 at^2$

where u is the initial velocity, t is the time of flight, a is the acceleration, s is the displacement.

Here, putting s= 20 m, u=0, $a=g=9.81 m/s^2$ in the equation of motion, we have

$20=0\timest+\frac 1 2 (9.81)t^2 \\\\\Rightarrow 20 = \frac 1 2 (9.81)t^2 \\\\\Rightarrow t^2 = (20\times2)/9.81 \\\\$

$\Rightarrow t = 2$ seconds (approx)

Now, put t=2 in the equation ( we have

$s=10/2=5$ m/s

Hence, the man must jump with 5 m/s horizontally to reach the pool.

6 0

3 years ago

energy expenditure due to physical activity generally accounts for __________ of total energy expenditure.

olga_2 [115]

Answer:

Energy expenditure due to physical activity generally accounts for 20% of total energy expenditure.

Explanation:

The total amount of energy your body uses daily is usually divided as follows:

1. Your Basal Metabolic Rate at rest (50-70%)

Basal Metabolic Rate is the number of calories required to keep your body functioning at rest

2. Consumption by your daily physical activities (20%)

3. Energy to digest food. (10-20%)

This energy has to be deducted from the overall energy content of the food itself.

Then, the answer is:

Energy expenditure due to physical activity generally accounts for 20% of total energy expenditure.

6 0

3 years ago

A gas is taken in a vessel which is then sealed. The gas is then heated. How will the

yanalaym [24]

Answer:

D The temperature, pressure and volume will all increase

3 0

4 years ago

Read 2 more answers

A 10-gram aluminum cube absorbs 677 joules when its temperature is increased from 50°c to 125°

kotegsom [21]

Answer : The specific heat of aluminum is, $0.90J/g^oC$

Solution : Given,

Heat absorbs = 677 J

Mass of the substance = 10 g

Final temperature = $125^oC$

Initial temperature = $50^oC$

Formula used :

$Q= m\times c\times \Delta T$

or,

$Q= m\times c\times (T_{final}-T_{initial})$

Q = heat absorbs

m = mass of the substance

c = heat capacity of aluminium

$T_{final}$ = final temperature

$T_{initial}$ = initial temperature

Now put all the given values in the above formula, we get the specific heat of aluminium.

$677g= (10g)\times c\times (125-50)^oC$

$c=0.9026J/g^oC=0.90J/g^oC$

Therefore, the specific heat of aluminum is, $0.90J/g^oC$

7 0

3 years ago

Read 2 more answers

If the rotation of a planet of radius 5.32 × 106 m and free-fall acceleration 7.45 m/s 2 increased to the point that the centrip

leonid [27]

Answer:

v = 6295.55 m/s

Explanation:

Given that,

The radius of a planet, $r=5.32\times 10^6\ m$

The free fall acceleration of the planet, a = 7.45 m/s²

We need to find the tangential speed of a person standing at the equator.

Also, the centripetal acceleration was equal to the gravitational acceleration at the equator.

We know that,

Centri[etal acceleration,

$a=\dfrac{v^2}{r}\\\\v=\sqrt{ar}\\\\v=\sqrt{5.32\times10^6\times 7.45}\\\\v=6295.55\ m/s$

So, the tangential speed of the person is equal to 6295.55 m/s.

3 0

3 years ago