Answer:
The phase difference between yA and yB is 
Step-by-step explanation:
Given harmonic modeled as :
yA = 8 sin(2t - 
) And
yB = 8 sin(2t - 
)
The function as written as :
y = a sin(ωt - Ф) where Ф is phase difference
So , phase difference between yA and yB = ( Ф_1 - Ф_2 )
Or phase difference between yA and yB = ( - + )
Or, phase difference between yA and yB = 
I.e phase difference between yA and yB =
Hence The phase difference between yA and yB is Answer
Given the function f (x) = 3x, find the value of f-1 (81).
For this case, the first thing you should do is rewrite the function.
We have then:
y = 3 ^ x
From here, we clear the value of x:
log3 (y) = log3 (3 ^ x)
log3 (y) = x
Then, we rewrite the function again:
f (x) ^ - 1 = log3 (x)
Now, we evaluate the inverse function for x = 81:
f (81) ^ - 1 = log3 (81)
f (x) ^ - 1 = 4
Answer:
the value of f-1 (81) is:
f (x) ^ - 1 = 4
48% is 54.72 of 144
Hope it helped
Answer:
6825
Step-by-step explanation:
From the equation, the series is a geometric series, such that
a = 5
r = 4
n = 6
sum of a geometric series is a(r^n - 1)/(r - 1)
therefore,
sum of the series is 5 x (4^6 - 1) / (4 - 1)
= 5 x (4096 - 1) / 3
= 5 x 4095 / 3
= 6825
Answer:
24,150
Step-by-step explanation:
7% of 345,000 = 24,150
