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1 year ago

This figure consists of a rectangle and semicircle.

Mathematics

1 answer:

noname [10]1 year ago

3 0

Answer:

Step-by-step explanation:

A = LW + ½πr²

A = 15(12) + ½(3.14)(12²/4)

A = 180 + 56.52

A = 236.52 m²

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Please help ASAP thank uob so much good day

Tomtit [17]

Answer:

vasd

Step-by-step explanation:

8 0

3 years ago

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One coin in a collection of 65 has two heads. The rest are fair. If a coin, chosen at random from the lot and then tossed, turns

geniusboy [140]

Answer:

P=1/65.

Step-by-step explanation:

We knaow that one coin in a collection of 65 has two heads. If a coin, chosen at random from the lot and then tossed, turns up heads 6 times in a row. We calculate the probability that it is the two-headed coin.

We calculate the number of possible combinations:

$C_1^{65}=\frac{65!}{1!(65-1)!}=65$

Number of favorable combinations is 1.

Therefore, the probability is

P=1/65.

6 0

2 years ago

USPshnik [31]

Answer:

$17,500 at 8%
$17,500 at 14%

Step-by-step explanation:

The fraction that needs to be invested at the higher rate is ...

(11% - 8%)/(14% -8%) = 3%/6% = 1/2

Half the money should be invested at each of the rates:

$17,500 for 8% return

$17,500 for 14% return.

_____

If you let x represent the amount at the higher rate, then the total return is ...

14%x + 8%(35000 -x) = 11%(35000)

(14% -8%)x = (11% -8%)(35000) . . . . subtract 8%·35000

x = (11% -8%)/(14% -8%)×35000 . . . . divide by the coefficient of x

Note that this formula is exactly the one we started with, above.

4 0

2 years ago

8 – (x + 4) = 2<br> determine the value of x in the equation below

Bess [88]

Answer:

8 -1(x+4)=2

8-x-4=2

x= 2+4-8

x=-2

4 0

2 years ago

Read 2 more answers

A big lockers above a smaller locker they both have 0.5 m wide and 0.6 m deep Big lockers 1.2 m tall and small lockers half of t

Tomtit [17]

Answer:

$0.54\,\,m^3$

Step-by-step explanation:

Given: Dimensions of a big locker are 0.5 m × 0.6 m × 1.2 m

Dimensions of a small locker are 0.5 m × 0.6 m × $\frac{1.2}{2}=0.6\,\,m$ (as height of small locker is half the height of big locker )

To find: total volume of one big locker and one small locker

Solution:

Volume of cuboid = length × breadth × height

Total volume of one big locker and one small locker = Total volume of one big locker + total volume of one small locker

= $0.5\times 0.6\times 1.2+0.5\times 0.6\times 0.6$

$=0.5\times 0.6\left ( 1.2+0.6 \right )\\=0.3(1.8)\\=0.54\,\,m^3$

4 0

2 years ago

Read 2 more answers