Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
Two whole numbers
plssss mark as brilliant
Let the number of hamburgers sold be "h" and the number of cheeseburgers be "2h" as it was two time as the humbugers .form equation frome it '2h+h=387".comp the like terms which gives you 3h=387 divide each side by 3 which gives you h=129 which is equal to the number hambyrgers .multiply 129 by 2 to get the number of cheeseburgers which is 258
It will be c because it was reflected
