Answer:
11/12
Step-by-step explanation:
1 2/3=5/3
5/3-3/4=20/12-9/12=11/12
Using the <u>normal distribution and the central limit theorem</u>, it is found that the interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
In a normal distribution with mean
and standard deviation
, the z-score of a measure X is given by:
- It measures how many standard deviations the measure is from the mean.
- After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
- By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation
.
In this problem:
- The mean is of
.
- The standard deviation is of
.
- Sample of 100, hence

The interval that contains 95.44% of the sample means for male students is <u>between Z = -2 and Z = 2</u>, as the subtraction of their p-values is 0.9544, hence:
Z = -2:

By the Central Limit Theorem




Z = 2:




The interval that contains 99.44% of the sample means for male students is (3.4, 3.6).
You can learn more about the <u>normal distribution and the central limit theorem</u> at brainly.com/question/24663213
A- 5
B- 4
C- 3
D- 8
E- -4
I think these are right hopes it help
Answer:
-1
Step-by-step explanation:
96=84-12r
96-84=-12r
12=-12r
-1=x
x=-1
Answer:
C)10.2
Step-by-step explanation:
A is not the correct answer because it is way less than 10.2 and 10.3.
B is not correct because although it has 10, the numbers behind the points are in the ten thousandths place, being less than 10.2.
Then, D is incorrect because it is bigger than the range between 10.2 and 10.3
<em><u>Leaving C with your correct answer</u></em>