The <em>speed</em> intervals such that the mileage of the vehicle described is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h]
<h3>How to determine the range of speed associate to desired gas mileages</h3>
In this question we have a <em>quadratic</em> function of the <em>gas</em> mileage (g), in miles per gallon, in terms of the <em>vehicle</em> speed (v), in miles per hour. Based on the information given in the statement we must solve for v the following <em>quadratic</em> function:
g = 10 + 0.7 · v - 0.01 · v² (1)
An effective approach consists in using a <em>graphing</em> tool, in which a <em>horizontal</em> line (g = 20) is applied on the <em>maximum desired</em> mileage such that we can determine the <em>speed</em> intervals. The <em>speed</em> intervals such that the mileage of the vehicle is 20 miles per gallon or less are: v ∈ [10 mi/h, 20 mi/h] ∪ [50 mi/h, 75 mi/h].
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Answer:
Step-by-step explanation:
y is always (1/3) of x.
Thus, if x = 0, y = 0; if x = 1, y = (1/3)(1) = 1/3, and so on. The corresponding ordered pairs are (0, 0), (1, 1/3), (-2, -2/3)
- The opposite sides are parallel and congruent. - The diagonals bisect each other.
- There are 4 right angles. - The diagonals are congruent.
- Show that both pairs of opposite sides are congruent.
Answer:
≈ 13.98%
Step-by-step explanation:
As the total population is 5769 in the initial period, you must find the percentage that repesents 4963 that is the expected population.
4963/5769=0.8602
Then you multiply it by 100 to transform it into percentage
0.8602*100=86.02%
Then it's just necesary to subtract that from 100% and that numbers is the percentage of decrease
100% - 86.02% = 13.98%
Also you can say that is approximately 14%
Answer:
Step-by-step explanation:
eq of a line through (x1,y1) and slope m is
y-y1=m(x-x11)
y+3=3(x+4)
y+3=3x+12
y=3x+12-3
y=3x+9