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3 years ago

7

PLEASE HELP ME ASAP A.20 B.22 C.7 D.11 Amosc pimp.chriz

1 answer:

Lady bird [3.3K]3 years ago

4 0

It’s 11! The answer is D

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jen picked 3/4 of a gallon of strawberries in a half of hour .if she keeps picking strawberries at the same rate.how many gallon

ivolga24 [154]

3 gallons of strawberries.

3/4 * 4/1 = 12/4 = 3

or you can use the butterfly method on the fours and get

3/1 * 1/1 = 3

5 0

3 years ago

Jane is playing a game in which he spins a spinner with 6 equal-sized slices numbered 1 through 6. The spinner stops on a number

sleet_krkn [62]

Answer:

The expected value of playing the game is $0.75.

Step-by-step explanation:

The expected value of a random variable is the weighted average of the random variable.

The formula to compute the expected value of a random variable <em>X</em> is:

$E(X)=\sum x\cdot P(X=x)$

The random variable <em>X</em> in this case can be defined as the amount won in playing the game.

The probability distribution of <em>X</em> is as follows:

Number on spinner: 1 2 3 4 5 6

Amount earned (<em>X</em>): $1 $4 $7 $10 -$8.75 -$8.75

Probability: 1/6 1/6 1/6 1/6 1/6 1/6

Compute the expected value of <em>X</em> as follows:

$E(X)=\sum x\cdot P(X=x)$

$=(1\times \frac{1}{6})+(4\times \frac{1}{6})+(7\times \frac{1}{6})+(10\times \frac{1}{6})+(-8.75\times \frac{1}{6})+(-8.75\times \frac{1}{6})$

$=\frac{1}{6}+\frac{4}{6}+\frac{7}{6}+\frac{10}{6}-\frac{8.75}{6}-\frac{8.75}{6}$

$=\frac{1+4+7+10-8.75-8.75}{6}$

$=0.75$

Thus, the expected value of playing the game is $0.75.

5 0

3 years ago

This is characterized by the symbol <, and is always read from left to right. Example: The phrase Cindy's wages were ______ $

Licemer1 [7]

The term is less than. Think about it this way next time, the mouth is open to the bigger number because it wants to eat the bigger number. So the number facing the tail is always less than.

3 0

3 years ago

Read 2 more answers

A raffle offers one $8000.00 prize, one $4000.00 prize, and five $1600.00 prizes. There are 5000 tickets sold at $5 each. Find t

Harman [31]

Answer:

The expectation is $E(1 )= -\$ 1$

Step-by-step explanation:

From the question we are told that

The first offer is $x_1 = \$ 8000$

The second offer is $x_2 = \$ 4000$

The third offer is $\$ 1600$

The number of tickets is $n = 5000$

The price of each ticket is $p= \$ 5$

Generally expectation is mathematically represented as

$E(x)=\sum x * P(X = x )$

$P(X = x_1 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_1 ) = 0.0002$

Now

$P(X = x_2 ) = \frac{1}{5000}$ given that they just offer one

$P(X = x_2 ) = 0.0002$

Now

$P(X = x_3 ) = \frac{5}{5000}$ given that they offer five

$P(X = x_3 ) = 0.001$

Hence the expectation is evaluated as

$E(x)=8000 * 0.0002 + 4000 * 0.0002 + 1600 * 0.001$

$E(x)=\$ 4$

Now given that the price for a ticket is $\$ 5$

The actual expectation when price of ticket has been removed is

$E(1 )= 4- 5$

$E(1 )= -\$ 1$

4 0

3 years ago

Use these four examples to summarize the result when you add a natural number and an integer:

DerKrebs [107]

When you add an integer and a natural number, you always get an integer.

4 0

3 years ago