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nikklg [1K]
3 years ago
13

Given f(x) and g(x) = f(k⋅x), use the graph to determine the value of k2-21/2-1/2

Mathematics
1 answer:
Umnica [9.8K]3 years ago
3 0

Answer:

Step-by-step explanation:

Using the graph we can notice something

let's take the abscissa  -2 and -4

  • the ordinate that goes with -2 using g is 0
  • the ordinate that goes with  -4 using f is 0

so we can say that :

f(-4)=g(-2)

wait we khow that g(x)=f(k*x)

so x= -2 then let's replace it in the expression : f(k*x)

we get f(-4)=g(-2)=f[k*(-2)]

let's solve the equation: -2k = -4

                                               k = -4/-2

                                                k=2

so finally we get k=2

let's check :

from the graph we get :

  • f(-2)=2
  • g(-1)=2

we have (-1)*2 = -2

so it is true

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mel-nik [20]

Answer:

k = 5/6

Step-by-step explanation:

First, we can make this have the form of a quadratic function, or ax²+bx+c=0. To do this, we can first subtract 10x from both sides to get

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Next, we can add 6 to both sides, resulting in

(2k+1)x²-8x+6 = 0

For a quadratic function of form ax²+bx+c=0, we can see that a=2k+1, b=-8, and c=6. We can then apply the quadratic equation, or

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x= (8 ± √(64-4(6)(2k+1)))/(2*(2k+1))

=  (8 ± √(64-(48k+24)))/(4k+2)

=  (8 ± √(40-48k))/(4k+2)

For the roots to be equal, we must have the two roots equal to each other. We can write this as

(8 + √(40-48k))/(4k+2) = (8 - √(40-48k))/(4k+2)

multiply both sides by (4k+2) to remove the denominator

8+√(40-48k) = 8 - √(40-48k)

subtract 8 from both sides to isolate the square roots

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√(40-48k) = 0

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add 48k to both sides to isolate the k and its coefficient

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divide both sides by 48 to isolate k

k = 40/48 = 5/6

7 0
3 years ago
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Alchen [17]
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but if you had
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exaple

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anothe rexample with placeholders
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6 0
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