You can just simplify to make an equivalent equation:
(2)(3x + 8) = 5 ⇒ 6x + 16 = 5
Answer:
Hope it helped,
BioTeacher101
<em>(If you have any questions feel free to ask them in the comments)</em>
Answer:
19 = x
Step-by-step explanation:
The square of the tangent segment = The product of (whole secant segment) (the outside part of the secant segment)
BD²= (BA)(BE)
8² = (4 + x - 7) (4) BA = BE + EB
8² = (x - 3)(4)
64 = 4x - 12
64 + 12 = 4x
76 = 4x
19 = x
I don’t know what you want me to solve
Answer:
8q + 6 = 8*2 + 6 = 16 + 6 = 22
Polygon HJKL has vertices H(-3, 4), J(2, 6), K(2, 1), and L(-3, -1). What are the slopes of sides HJ, JK, KL, and LH and how wou
aleksklad [387]
<span> the slopes of sides HJ, JK, KL, and LH and how would you classify HJKL?</span>
