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iogann1982 [59]
3 years ago
8

A theater has 30 rows of seats. There are 22 seats in the first row, 26 in the second row, 30 in the third row, etc. How many pe

ople will the theater hold ?
Mathematics
2 answers:
OLga [1]3 years ago
4 0

Arithmetic Sequence

rows ---------32-n

first term ------------26-----------a

d---------------------------4

Sn = n/2( 2a+(n-1)d)

=32/2 (2*26+(31)4)

=16(52+124)

=16(176)

=2816 seats

solong [7]3 years ago
4 0

Total rows of seats, n = 30 rows of seats

First row, A1 = 22 seats

Second row, A2 = 26 seats

Third row, A3 = 30 seats

d = A3 - A2 = A2 - A1 = 4

then,

Sn = n/2 (2A1 + (n - 1)d)

Sn = 30/2 (2*22 + (30 - 1)4)

Sn = 15(44 + 116)

Sn = 2400 people

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weqwewe [10]
Take x-2 and insert it into 2x^2 + 3x-2 where the x is located 
2x^2 + 3x-2
2(x-2)^2 + 3(x-2)-2

Now work out 2(x-2)^2 + 3(x-2)-2 also follow PEMDAS
2(x-2)^2 + 3(x-2)-2 
Since (x-2)^2 is an Exponent, lets work with that first and expand (x-2)^2.
(x-2)^2
(x -2)(x-2)
x^2 -4x + 4
Now Multiply that by 2 because we have that in 2(x-2)^2
(x-2)^2  =  x^2 -4x + 4
2(x-2)^2  =  2(x^2 -4x + 4)
2(x^2 -4x + 4) = 2x^2 - 8x + 8
2x^2 - 8x + 8

Now that 2(x-2)^2 is done lets move on to 3(x-2).

Use the distributive property and distribute the 3
3(x-2) = 3x - 6

All that is left is the -2 

Now lets put it all together 
2(x-2)^2 + 3(x-2)-2

2x^2 - 8x + 8 + 3x - 6 - 2

Now combine all our like terms 
2x^2 - 8x + 8 + 3x - 6 - 2
Combine:  2x^2      =  2x^2 
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So all we have left is
2x^2 - 5x





5 0
3 years ago
The height of a ball thrown vertically upward from a rooftop is modelled by h(t)= -4.8t^2 + 19.9t +55.3 where h (t) is the balls
nikitadnepr [17]

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

<h3>How to determine the maximum height of the ball</h3>

Herein we have a <em>quadratic</em> equation that models the height of a ball in time and the <em>maximum</em> height represents the vertex of the parabola, hence we must use the <em>quadratic</em> formula for the following expression:

- 4.8 · t² + 19.9 · t + (55.3 - h) = 0

The height of the ball is a maximum when the discriminant is equal to zero:

19.9² - 4 · (- 4.8) · (55.3 - h) = 0

396.01 + 19.2 · (55.3 - h) = 0

19.2 · (55.3 - h) = -396.01

55.3 - h = -20.626

h = 55.3 + 20.626

h = 75.926 m

By applying the <em>quadratic</em> formula and discriminant of the <em>quadratic</em> formula, we find that the <em>maximum</em> height of the ball is equal to 75.926 meters.

To learn more on quadratic equations: brainly.com/question/17177510

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6 0
2 years ago
Please solve this...I can;t do it do it
yanalaym [24]

Answer:

Area = 867 meters

Step-by-step explanation:

You have a rectangle. This means opposite sides are equal. If you set these expressions equal to each other, you will get two equations with two unknowns, x and y. Next, solve the system of equations to find x and y. Then, use the values to find the length and width of the rectangle. Last, multiply length × width to find the area.

8 0
2 years ago
I’m not asking for much :(
Vinvika [58]

Answer:

c

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
A small factory planned to produce a batch of men’s shirts in 8 days. But producing 10 more shirts per day than planned, they fi
a_sh-v [17]

In unit of batches over days, let r be the planned rate and R be the actual increased rate. The difference between R and r is described as 10 shirts per day.

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Planned              r                          8                           1

Actual                 R                         7                            1


\left[\begin{array}{c}r=1/8&R=1/7&R-r=HowManyBatchesInTenShirts\end{array}\right]

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(1/56)*Batches=10*Shirts

OneBatch=560*Shirts

Hope This Helps!!!

4 0
3 years ago
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