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iogann1982 [59]
3 years ago
8

A theater has 30 rows of seats. There are 22 seats in the first row, 26 in the second row, 30 in the third row, etc. How many pe

ople will the theater hold ?
Mathematics
2 answers:
OLga [1]3 years ago
4 0

Arithmetic Sequence

rows ---------32-n

first term ------------26-----------a

d---------------------------4

Sn = n/2( 2a+(n-1)d)

=32/2 (2*26+(31)4)

=16(52+124)

=16(176)

=2816 seats

solong [7]3 years ago
4 0

Total rows of seats, n = 30 rows of seats

First row, A1 = 22 seats

Second row, A2 = 26 seats

Third row, A3 = 30 seats

d = A3 - A2 = A2 - A1 = 4

then,

Sn = n/2 (2A1 + (n - 1)d)

Sn = 30/2 (2*22 + (30 - 1)4)

Sn = 15(44 + 116)

Sn = 2400 people

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The combined average weight of an okapi and a llama is 450450 kilograms. The average weight of 33 llamas is 190190 kilograms mor
Nataliya [291]

Answer:

Okapi 290 kg

Llama 160 kg


Step-by-step explanation:

Let weight of each llama be  l

Let weight of each okapi be  o


<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>

<em>l+o=450</em>

<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>

<em>3l-190=o</em>


Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

l+o=450\\l+(3l-190)=450\\l+3l-190=450\\4l=450+190\\4l=640\\l=\frac{640}{4}=160


Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

o=3l-190\\o=3(160)-190\\o=290

Each okapi weigh 290 kg

5 0
3 years ago
Let f ( x ) = 2 x − 1 , g ( x ) = 3 x , and h ( x ) = x ^2 + 1 , what is h( h ( 5) ) ?
strojnjashka [21]
First you would solve for h(5) by plugging in 5 as your x, then solving it.

h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26

Next you would multiply the 26 by the individual h, which is basically h(1).

h(1) = 1^2 + 1
h(1) = 2

Lastly you multiply your h(1) value by the h(5) value to get your answer.

h(1) • h(5) = 26 • 2
h[h(5)] = 52
7 0
3 years ago
Please help yall I gotta pass this test
Stella [2.4K]

Answer:

12.05

is the answer I think

7 0
2 years ago
Solve (200 + 200) √100​
mart [117]

Answer:

4000

Step-by-step explanation:

200 + 200 {100

400 × 10

4000

4 0
2 years ago
Read 2 more answers
Find dx/dt when y=2 and dy/dt=1, given that x^4=8y^5-240<br><br> dx/dt=
katrin2010 [14]

Answer:

The value of \frac{dx}{dt} is \frac{160}{x^3}.

Step-by-step explanation:

The given equation is

x^4=8y^5-240

We need to find the value of \frac{dx}{dt}.

Differentiate with respect to t.

4x^3\frac{dx}{dt}=8(5y^4)\frac{dy}{dt}-0              [\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]

4x^3\frac{dx}{dt}=40y^4\frac{dy}{dt}

It is given that y=2 and dy/dt=1, substitute these values in the above equation.

4x^3\frac{dx}{dt}=40(2)^4(1)

4x^3\frac{dx}{dt}=40(16)(1)

4x^3\frac{dx}{dt}=640

Divide both sides by 4x³.

\frac{dx}{dt}=\frac{640}{4x^3}

\frac{dx}{dt}=\frac{160}{x^3}

Therefore the value of \frac{dx}{dt} is \frac{160}{x^3}.

4 0
3 years ago
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