Answer:
Okapi 290 kg
Llama 160 kg
Step-by-step explanation:
Let weight of each llama be 
Let weight of each okapi be 
<em>Given, combined weight of 1 okapi and 1 llama is 450, we can write:</em>
<em>
</em>
<em>Also, average weight of 3 llama is 190 more than the average weight of 1 okapi, thus we can write:</em>
<em>
</em>
Now, substituting 2nd equation into 1st equation, we can solve for weight of 1 llama:

Each llama weights 160 kg, now using this and plugging into 2nd equation, we get weight of 1 okapi to be:

Each okapi weigh 290 kg
First you would solve for h(5) by plugging in 5 as your x, then solving it.
h(5) = 5^2 + 1
h(5) = 25 + 1
h(5) = 26
Next you would multiply the 26 by the individual h, which is basically h(1).
h(1) = 1^2 + 1
h(1) = 2
Lastly you multiply your h(1) value by the h(5) value to get your answer.
h(1) • h(5) = 26 • 2
h[h(5)] = 52
Answer:
4000
Step-by-step explanation:
200 + 200 {100
400 × 10
4000
Answer:
The value of
is
.
Step-by-step explanation:
The given equation is

We need to find the value of
.
Differentiate with respect to t.
![[\because \frac{d}{dx}x^n=nx^{n-1},\frac{d}{dx}C=0]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Cfrac%7Bd%7D%7Bdx%7Dx%5En%3Dnx%5E%7Bn-1%7D%2C%5Cfrac%7Bd%7D%7Bdx%7DC%3D0%5D)

It is given that y=2 and dy/dt=1, substitute these values in the above equation.



Divide both sides by 4x³.


Therefore the value of
is
.