Stem|leaf data: 11 12 13 21 22 23
1|1 2 3
2| 1 2 3
You're basically just splitting the numbers up. Tens in the stem row and ones in the leaf row. I hope this helps you!
Answer:


And the best option would be:
D. (0.191 to 0.249)
Step-by-step explanation:
For this case we know that the mean is:

And the standard error is given by:

We want to construct a 68% confidence interval so then the significance level would be :
and
. The confidence interval is given by:

Now we can find the critical value using the normal standard distribution and we got looking for a quantile who accumulate 0.16 of the area on each tail and we got:

And replacing we got:


And the best option would be:
D. (0.191 to 0.249)
Answer:
Step-by-step explanation:
b(a + 1) + a = b*a + b + a = ab + b + a
1) b(2a +1 ) = b*2a + b*1 = 2ab + b Not equivalent.
2)a + (a +1)*b = a + ab+ b Equivalent
3) (a +1)(b+ a) = a*(b +a) + 1*(b+a) = ab+ a² +b + a Not equivalent.
4) (a + 1)b + a = ab+ b + a Equivalent
5) a + b(a+1) = a +ab + b Equivalent
6) a + (a +1) + b = a + a + 1 + b = 2a + 1 +b Not equivalent.
7) a(b +1) + b = ab + a + b Equivalent
Answer:
C
Step-by-step explanation:
The multiples of 3 are
3, 6, 9, 12, 15, ...........
The terms form an arithmetic sequence with common difference of 3.
The sum to n terms is
=
[2a₁ + (n - 1)d ]
where a₁ is the first term and d the common difference
Here a₁ = 3 and d = 3, thus
=
[ (2 × 3) + (139 × 3) ]
= 70(6 + 417) ] = 70 × 423 = 29610 → C
A dime weighs 2.268 grams, and a quarter weighs 5.670 grams.