picture unclear because it is to find the sum of consecutive numbers 1 to 100, you multiply the number of sets (50) by the sum of each set (101): 101(50)=5050.{\displaystyle 101(50)=5050.} So, the sum of consecutive number 1 through 100 is 5,050 .
Answer: S<\-2
Hope i was some help.
Step-by-step explanation: sorry I can’t put the right sign my keybored won’t let me but you know what it stands for.
3s+6s</-5(s+2)
start off with -5(s+2) you multiply -5 with s and it is -5s then you do the same for +2 take -5 and multiply by +2 pos times a neg is always a neg so it’s -10.
3s+6<\-5s-10
So you have to get rid of the -5s so your going to do the inverse which is add 5 to -5 and it will get rid of -5s but then you have to add 5 to 3s and that will be 8s.
8s+6</-10
Now your going to get rid of the +6 and to do that you do the inverse you subtract 6 and it will get rid of it now you have to do the same for -10 so you will subtract 6 to -10 and that will equal -16.
Now you have to divide!
8s/8 </ -16/8
And it should equal s <\-2
Answer:
16
Step-by-step explanation:
12 - 3 = 9
9 + 7 = 16
Answer: I doubt your in it anymore
Step-by-step explanation:
