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KonstantinChe [14]
1 year ago
10

Two diced are rolled. What is the probability that the sum of two numbers on the dice will be 4? 11/121/40

Mathematics
1 answer:
makkiz [27]1 year ago
3 0

Each die has 6 possible outcomes (the numbers from 1 to 6).

If we roll two dices, the total number of outcomes is 6 * 6 = 36.

From these outcomes, the ones that have a sum of 4 are:

(1, 3), (2, 2) and (3, 1).

So, if we have 3 wanted outcomes from a total of 36, the probability is:

P=\frac{3}{36}=\frac{1}{12}

Therefore the correct option is the second one.

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I'm stuck. Can anyone help please?
Serjik [45]

log₉(<em>x</em> - 7) + log₉(<em>x</em> - 7) = 1

2 log₉(<em>x</em> - 7) = 1

log₉(<em>x</em> - 7) = 1/2

Take the base-9 antilogarithm of both sides; in other words, make both sides powers of 9:

9^{\log_9(x-7)} = 9^{1/2}

9^{1/2} can also be written as √9 = 3, and b^{\log_b(a)}=a, so the equation reduces to

<em>x</em> - 7 = 3

Solve for <em>x</em> :

<em>x</em> = 10

7 0
3 years ago
Women appear to marry about 3 years younger than men, but the two distributions are very similar in shape and spread.
Irina18 [472]

The brief report about what the attached data in the box plot shows that: "Women appear to marry around three years younger than males, although the shape and dispersion of the two distributions are extremely comparable."

<h3>What is a box plot?</h3>

A boxplot is a type of graph that shows how the values in the data are distributed.

A boxplot is a standardized technique of representing data distribution based on a five-number summary ("minimum", first quartile (Q1), median, third quartile (Q3), and "maximum").

It can provide information about your outliers and their values.

Learn more about box plots at;
brainly.com/question/14277132
#SPJ1

Full Question:

In​ 1975, did men and women marry at the same​ age? Here are boxplots of the age at first marriage for a sample of U.S. citizens then. Write a brief report discussing what these data show.

5 0
2 years ago
The position function of a particle in rectilinear motion is given by s(t) = 2t3 – 21t2 + 60t + 3 for t ≥ 0 with t measured in s
Norma-Jean [14]

The positions when the particle reverses direction are:

s(t_1)=55ft\\\\s(t_2)=28ft

The acceleraton of the paticle when reverses direction is:

a(t_1)=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=18\frac{ft}{s^{2}}

Why?

To solve the problem, we need to remember that if we derivate the position function, we will get the velocity function, and if we derivate the velocity function, we will get the acceleration function. So, we will need to derivate two times.

Also, when the particle reverses its direction, the velocity is equal to 0.

We are given the following function:

s(t)=2t^{3}-21t^{2}+60t+3

So,

- Derivating to get the velocity function, we have:

v(t)=\frac{ds}{dt}=(2t^{3}-21t^{2}+60t+3)\\\\v(t)=3*2t^{2}-2*21t+60*1+0\\\\v(t)=6t^{2}-42t+60

Now, making the function equal to 0, to find the times when the particle reversed its direction, we have:

v(t)=6t^{2}-42t+60\\\\0=6t^{2}-42t+60\\\\0=t^{2}-7t+10\\(t-5)*(t-2)=0\\\\t_{1}=5s\\t_{2}=2s

We know that the particle reversed its direction two times.

- Derivating the velocity function to find the acceleration function, we have:

a(t)=\frac{dv}{dt}=6t^{2}-42t+60\\\\a(t)=12t-42

Now, substituting the times to calculate the accelerations, we have:

a(t_1)=a(2s)=12*2-42=-18\frac{ft}{s^{2}}\\ \\a(t_2)=a(5s)=12*5-42=18\frac{ft}{s^{2}}

Now, substitutitng the times to calculate the positions, we have:

s(t_1)=2*(2)^{3}-21*(2)^{2}+60*2+3=16-84+120+3=55ft\\\\s(t_2)=2*(5)^{3}-21*(5)^{2}+60*5+3=250-525+300+3=28ft

Have a nice day!

3 0
3 years ago
Carlos has an aquarium which is 45 cm long, 32 cm wide, and 35 cm high. How much water can the aquarium hold?
Ivenika [448]

Answer:

volume =l×b×h

45cm×32cm×35cm=48,960cm³

8 0
3 years ago
Read 2 more answers
The triangular faces of the peaks on a roof are congruent isosceles triangles with vertex angles U and V.
Rina8888 [55]

Answer:

<em> (a). ∠UXV, ∠XVY ; (b). UV = 8 m .</em>

Step-by-step explanation:

3 0
3 years ago
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