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dangina [55]
3 years ago
12

What polygon is obtained by graphing the given system of inequalities? What is the area of the polygon bounded by the inequaliti

es? y ≥ 1 x ≥ 1 y ≤ 4 x ≤ 6 The polygon obtained by graphing the system of inequalities is a . The area of the polygon bounded by the inequalities is square units.
Mathematics
1 answer:
aalyn [17]3 years ago
8 0
Hello,

Vertex are:
(1,1),(6,1),(1,4),(6,4=
Area=(6-1)*(4-1)=5*3=15

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In a recent year, one United States dollar was equal to about 82 Japanese yen. How many Japanese yen are equal to $100? $1,000?
alexandr402 [8]
Well if $1=82 than $100 (which is 100 times 1) would equal 82·100=8,200
$1,000·82=82,000
$10,000·82=820,000 :) hope this helps!
8 0
3 years ago
Read 2 more answers
Suppose we want to choose five objects without replacement from 14 distinct objects if the order of the choices is taken into co
Elanso [62]

Answer:

why would i kn9w im, n9t smart

5 0
3 years ago
36 out of 100 randomly selected taxpayers knew about tax incentives for installing energy-saving furnaces. Find a 90% confidence
tresset_1 [31]

Answer:

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 100, \pi = \frac{36}{60} = 0.6

90% confidence level

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 - 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.28

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.36 + 1.645\sqrt{\frac{0.36*0.64}{100}} = 0.44

The 90% confidence interval for the population proportion who knew about the incentives is (0.28, 0.44).

7 0
3 years ago
The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh
Lina20 [59]

Answer:

B.)The volume of the triangular prism is not equal to the volume of the cylinder.

Step-by-step explanation:

Let A be the cross-sectional area of both congruent right triangular prism and right cylinder.

Since the prism has height 2 units, its volume V₁ = 2A.

Since the cylinder has height 6 units, its volume is V₂ = 6A

Dividing V₁/V₂ = 2A/6A =1/3

V₁ = V₂/3.

The volume of the prism is one-third the volume of the cylinder.

So, since the volume of the prism is neither double nor half of the volume of the cylinder nor is it equal to the volume of the cylinder, B is the correct answer.

So, the volume of the triangular prism is not equal to the volume of the cylinder.

5 0
3 years ago
2. A function fis graphed below, which consists of two semicircles and two linear pieces.
ivolga24 [154]
Ist b hope that helps
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2 years ago
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