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Svetllana [295]
3 years ago
5

3 1/4 as a fraction

Mathematics
1 answer:
ira [324]3 years ago
8 0

Answer: 3 1/4 as an improper fraction could be 13/4. Written as a fraction would be 3 1/4.

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2 Points
KonstantinChe [14]

Answer:

C

Step-by-step explanation:

The angle adjacent to x on XY = 115° ( corresponding angle )

This angle and x are adjacent and supplementary , thus

x = 180 - 115 = 65 → C

6 0
3 years ago
Read 2 more answers
A rectangular prism is filled with cubes that
Svet_ta [14]

Answer:

Find the volume of the rectangular prism and

divide by the volume of the cube.

Volume of cube = side measure ^3

Cube = (1/8)3 = 1/512

Volume of prism = Ixwxh

Prism (1/4)(1/2)(3/8) =3/64

3/64/1/512

3/64 x 512/1

3x 512/64

1536/64

24

6 0
2 years ago
What is the solution for xsquared= 64
nordsb [41]
Square root both sides and you get:
X=8
8 0
3 years ago
(x + 3)(x - 3) &gt; 0<br> (x + 4)(x + 2)
atroni [7]

there is no solution if the equation are put together but there is if they are done alone

first question and second question

The answer is in the picture above please mark me brainliest :)

7 0
4 years ago
A publication released the results of a study of the evolution of a certain mineral in the​ Earth's crust. Researchers estimate
san4es73 [151]

Answer:

a) E(A)=\frac{1+6}{2}=3.5 ppm

b) P(2.875

c) P(X

Step-by-step explanation:

If we work with the limits defined from 5 to 10 then part b and c from this question not makes sense. If we work with the limits 1 and 6 all the parts for the question makes sense because if we work with 5 and 10 the only thing that we can find is the expected value E(A) = \frac{5+10}{2}= 7.5

Assuming the following correct question : "A publication released the results of a study of the evolution of a certain mineral in the​ Earth's crust. Researchers estimate that the trace amount of this mineral x in reservoirs follows a uniform distribution ranging between 1 and 6 parts per million"

Solution to the problem

Let A the random variable that represent " amount of the mineral x ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,6)

Part a

For this uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+6}{2}=3.5 ppm

Part b

For this case we can use the cumulative distribution function for the uniform distribution given by:

F(X=x)= \frac{x-a}{b-a} = \frac{x}{6-1} =\frac{x-1}{5} , 1 \leq X \leq 6

And we want this probability:P(2.875Part c

For this case we want this probability:

P(X

3 0
3 years ago
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