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Travka [436]
3 years ago
14

How do I translate the product of h and 4 is subtracted from one-fifth of x is 35 to an equation?

Mathematics
1 answer:
kolezko [41]3 years ago
8 0

So we know that the word 'product' means multiplication, and that means that h and 4 are being multiplied. Also, one-fifth of x is another way of saying that one-fifth is being multiplied with x. So then we can construct the equation:

\frac{1}{5} x-(4*h)=35

And we can then simplify this by taking out the multiplication sign:

\frac{1}{5}x-4h=35

And so since we do not know what x or h is equal to, this is as far as we can go.

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$45

Step-by-step explanation:

$3 times 15 days = $45

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1/4 - 3/5 write your answer is simplest form
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A factory produced a batch of handheld video games, but 4% of the games were found to be defective. If the batch had 250 games i
nirvana33 [79]

Answer:

the answer is 240

Step-by-step explanation:

If 4% are defective, then out of a batch of 250, the number of defective is

4% x 250 = 4/100 x 250 = 10 defective

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8 0
3 years ago
6 points Emily’s family needs to rent a moving truck to move their belongings to a different house. The rental cost for Trucks-A
Alexxx [7]

Answer/Step-by-step explanation:

Equation to represent the daily rental cost for each type of truck can be written as follows:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Where, m = Emily's mileage

To determine the number of miles for which the truck cost the same amount, set both equations equal to each other and solve for m.

42 + 0.72m = 70 + 0.12m

Collect like terms

0.72m - 0.12m = 70 - 42

0.6m = 28

Divide both sides by 0.6

\frac{0.6m}{0.6} = \frac{28}{0.6}

m = 46.7

At approximately 47 miles, both trucks would cost the same amount.

Check:

Daily rental cost for Trucks-A-Lot = 42 + 0.72m

Plug in the value of x = 47

= 42 + 0.72(47) = $75.84 ≈ $76

Daily rental cost for Move-in-Truckers = 70 + 0.12m

Plug in the value of x = 47

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7 0
3 years ago
(ASAP PICTURE ADDED) What is the simplified form of the following expression?
bonufazy [111]

Answer:

option c is correct.

Step-by-step explanation:

7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{16x}\right)-3\left(\sqrt[3]{8x}\right)

WE need to simplify this equation.

Solve the parenthesis of each term.

=7\left\sqrt[3]{2x}\right-3\left\sqrt[3]{16x}\right-3\left\sqrt[3]{8x}\right

Now, We will find factors of the terms inside the square root

factors of 2: 2

factors of 16 : 2x2x2x2

factors of 8: 2x2x2

Putting these values in our equation:=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2X2 x}\right)-3\left(\sqrt[3]{2X2X2 x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2X2X2} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3] {2 x}\right)-3\left(\sqrt[3]{2^3} \sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2x}\right)-3*2\left(\sqrt[3] {2 x}\right)-3*2\left(\sqrt[3]{x}\right)\\=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)

Adding like terms we get:

=7\left(\sqrt[3]{2}\sqrt[3]{x}\right)-6\left(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right\\=(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\

(\sqrt[3] {2}\sqrt[3]{x})-6\left(\sqrt[3]{x}\right)\\can\,\,be \,\, written\,\, as\,\,\\(\sqrt[3] {2x})-6\left(\sqrt[3]{x}\right)

So, option c is correct

5 0
3 years ago
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