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katovenus [111]
3 years ago
15

One line passes through the points \blueD{(-3,-1)}(−3,−1)start color #11accd, (, minus, 3, comma, minus, 1, ), end color #11accd

and \blueD{(1,-9)}(1,−9)start color #11accd, (, 1, comma, minus, 9, ), end color #11accd. Another line passes through points \greenD{(1,4)}(1,4)start color #1fab54, (, 1, comma, 4, ), end color #1fab54 and \green{(5,6)}(5,6)start color #1fab54, (, 5, comma, 6, ), end color #1fab54. Are the lines parallel, perpendicular, or neither?
Mathematics
2 answers:
mart [117]3 years ago
8 0

Answer:

The lines are perpendicular

Step-by-step explanation:

we know that

If two lines are parallel, then their slopes are the same

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

Remember that

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}

<em>Find the slope of the first line</em>

we have the points

(-3,-1) and (1,-9)

substitute in the formula

m_1=\frac{-9+1}{1+3}

m_1=\frac{-8}{4}

m_1=-2

<em>Find the slope of the second line</em>

we have the points

(1,4) and (5,6)

substitute in the formula

m_2=\frac{6-4}{5-1}

m_2=\frac{2}{4}

Simplify

m_2=\frac{1}{2}

<em>Compare the slopes</em>

m_1=-2

m_2=\frac{1}{2}

Find out the product

m_1*m_2=(-2)(\frac{1}{2})=-1

therefore

The lines are perpendicular

Sunny_sXe [5.5K]3 years ago
4 0

Answer:

well that is very hard to read so who knows

Step-by-step explanation:

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