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3 years ago

Solve for indicated variable. V= 1/3πr^2h solve for r

1 answer:

8 0

$V=\frac{1}{3}\pi r^2h\\\\\frac{1}{3}\pi r^2h=V\ \ \ \ |multiply\ both\ sides\ by\ 3\\\\\pi r^2h=3V\ \ \ \ |divide\ both\ sides\ by\ \pi h\\\\r^2=\frac{3V}{\pi h}\Rightarrow\boxed{r=\sqrt{\frac{3V}{\pi h}}}$

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Given the functions f(n) = 11 and g(n) = (3/4)n − 1, combine them to create a geometric sequence, an, and solve for the 9th term

Elina [12.6K]

Answer:

12345

Step-by-step explanation:

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3 years ago

When two numbers have a sum equal to ___ the numbers are additive inverses example of __ + -9 =0 and 18 + __ = 0

Aliun [14]

Answer: Zero; 9; -18

Step-by-step explanation:

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3 years ago

The circumference of a circle can be found using the formula C = 2r. Which is an equivalent equation solved for r? r = C r = C(2

vaieri [72.5K]

Answer:

r equals StartFraction C Over 2 pi EndFraction

Step-by-step explanation:

we know that

The circumference of a circle is equal to

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where

r is the radius of the circle

Solve for r

That means -----> isolate the variable r

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$\frac{C}{2\pi}=\frac{2\pi r}{2\pi}$

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$\frac{C}{2\pi}=r$

Rewrite

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r equals StartFraction C Over 2 pi EndFraction

5 0

3 years ago

Read 2 more answers

Find a polynomial function of least degree having only real coefficients, a leading coefficient of 1, and roots of 2-√6 , 2+ √6

horsena [70]

Answer:

$x^{4} -18x^{3}+104x^{2} -172x-100$

Step-by-step explanation:

The 3 roots are given out of which 2 are real and 1 is imaginary. For a polynomial of least degree having real coefficients, it must have a complex conjugate root as the 4th root. Therefore, based on 4 roots, the least degree of polynomial will be 4. Finding the polynomial having leading coefficient=1 and solving it based on multiplication of 2 quadratic polynomials, we get:

$\\\\x_{1} = 2-\sqrt{6} \\x_{2} = 2+\sqrt{6} \\x_{3}=7-i \\x_{4}=7+i \\\\P(x)=1(x-x_{1})(x-x_{2} )(x-x_{3} )(x-x_{4} ) \\\\=(x-(2-\sqrt{6}))( x-(2+\sqrt{6} )) (x-(7-i))( x-(7+i))\\=((x-2)+\sqrt{6})( ( x-2)-\sqrt{6} ) ((x-7)+i)( (x-7)-i)\\=((x-2)^{2} -(\sqrt{6} )^{2} )((x-7)^{2}-(i)^{2})\\=(x^{2} -4x-2)(x^{2} -14x+50)\\=x^{4} -18x^{3}+104x^{2} -172x-100\\$

7 0

3 years ago

Dos cuadrados de lado

Kaylis [27]

La franja amarilla del rectángulo tiene un área de 30 centímetros cuadrados.

<h3>¿Cuál es el área de la franja amarilla del rectángulo?</h3>

En este problema tenemos un rectángulo formado por dos cuadrados que se traslapan uno al otro. La franja amarilla es el área en la que los cuadrados se traslapan. La anchura del rectángulo es descrita por la siguiente ecuación:

(10 - x) + 2 · x = 17

Donde x se mide en centímetros.

A continuación, despejamos x en la ecuación descrita:

10 + x = 17

x = 7

Ahora, el área de la franja amarilla se determina mediante la fórmula de area de un rectángulo:

A = b · h

Donde:

b - Base del rectángulo, en centímetros.
h - Altura del rectángulo, en centímetros.
A - Área del rectángulo, en centímetros cuadrados.

A = (10 - 7) · 10

A = 3 · 10

A = 30

El área de la franja amarilla del rectángulo es igual a 30 centímetros cuadrados.

Para aprender más sobre áreas de rectángulos: brainly.com/question/23058403

#SPJ1

8 0

1 year ago