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4 years ago

How many moles of methane are required to produce 22g co2 after combustion

1 answer:

8 0

(Not guaranteed correct answer)
Balanced equation for complete combustion of methane would be:
CH4 + 2O2 --> CO2 + 2H20

Amount of CO2:
22g / [12.0+2(16.0)]
= 0.5mol

Mole ratio can be represented as
CH4 = CO2

So 0.5 mol of CO2 = 0.5 mol of CH4 ??

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Find the potential energy of a 2 kg ball 15 m in the air.

amm1812

Answer:

294,3

Explanation:

$E=m*g*h$

While g = 9,81 m/s^2 then:

$E=2[kg]*9,81[\frac{m}{s^2} ]*15[m]=294,3 [J]$ [J]

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3 years ago

What is arcenic? Who can tell me!

Luda [366]

Explanation:

Arsenic is a solid chemical element that is used especially in wood preservatives, alloys, and semiconductors and is extremely toxic in both pure and combined forms.

A poisonous trioxide As2O3 or As4O6 of arsenic is used especially as an insecticide or weed killer.

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3 years ago

Read 2 more answers

Ammonium carbonate and iron(iii) nitrate are combined, solid iron(iii) carbonate and a solution of ammonium nitrate are formed.

Vanyuwa [196]

Answer:

The net ionic equation is: 3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).

Explanation:

For the mentioned reaction:

We have the Molecular reaction:

3(NH₄)₂CO₃(aq) + 2Fe(NO₃)₃(aq) → Fe₂(CO₃)₃(s) + 6NH₄NO₃(aq)

We have the total ionic reaction:

6NH₄⁺(aq) + 3CO₃²⁻(aq) + 2Fe³⁺(aq) + 6NO₃⁻ → Fe₂(CO₃)₃(s) + 6NH₄⁺(aq) + 6NO₃⁻(aq).

NH₄⁺(aq) and NO₃⁻(aq) are spectator ions that are not changed through the reaction and still dissolved in the medium, so they can be omitted to get the net ionic equation.

So, the net ionic equation is:

3CO₃²⁻(aq) + 2Fe³⁺(aq) → Fe₂(CO₃)₃(s).

6 0

3 years ago

At a particular temperature a 2.00-L flask at equilibrium contains 2.80 ✕ 10-4 mol N2, 2.50 ✕ 10-5 mol O2, and 2.00 ✕ 10-2 mol N

zhenek [66]

Answer : The value of equilibrium constant (K) is, $5.71\times 10^4$

Explanation :

First we have to calculate the concentration of $N_2,O_2\text{ and }N_2O$

$\text{Concentration of }N_2=\frac{\text{Moles of }N_2}{\text{Volume of solution}}=\frac{2.80\times 10^{-4}mol}{2.00L}=1.4\times 10^{-4}M$

and,

$\text{Concentration of }O_2=\frac{\text{Moles of }O_2}{\text{Volume of solution}}=\frac{2.50\times 10^{-5}mol}{2.00L}=1.25\times 10^{-5}M$

and,

$\text{Concentration of }N_2O=\frac{\text{Moles of }N_2O}{\text{Volume of solution}}=\frac{2.00\times 10^{-2}mol}{2.00L}=1.00\times 10^{-2}M$

Now we have to calculate the value of equilibrium constant (K).

The given chemical reaction is:

$N_2(g)+O_2(g)\rightarrow 2N_2O(g)$

The expression for equilibrium constant is:

$K=\frac{[N_2O]^2}{[N_2][O_2]}$

Now put all the given values in this expression, we get:

$K=\frac{(1.00\times 10^{-2})^2}{(1.4\times 10^{-4})\times (1.25\times 10^{-5})}$

$K=5.71\times 10^4$

Thus, the value of equilibrium constant (K) is, $5.71\times 10^4$

7 0

4 years ago

The constant- pressure heat capacity of a sample of a perfect gas was found to vary with temperature according to the expression

vivado [14]

A perfect gas, commonly known as an ideal gas, would be a gas that, in physical behavior, conforms towards the general gas law, which would be a specific, idealized relationship between pressure, volume, and temperature, and further calculation can be defined as follows:

For question a:

$q=\int C_p dT=\int^{200+273K}_{25+273 K} [20.17 + 0.3665 (\frac{T}{K})] dT JK^{-1}\\\\$

$=[(20.17)T +\frac{1}{2}(0.3665)\times (\frac{T^2}{K})]^{473K}_{298K}\ JK^{-1}\\\\=[(20.17)\times(473-293) +\frac{1}{2}(0.3665)\times (473^2-293^2)]\ J\\\\=[(20.17)\times(180) +\frac{1}{2}(0.3665)\times (223729-85849)]\ J\\\\=[3630.6 +(0.18325)\times (137880)]\ J\\\\=[3630.6 +25266.51]\ J\\\\=[28897.11]\ J\\\\=[28.8 \times 10^{3}] \ J\\\\$

$W= -p \Delta V= -nR\Delta T= -(1.00\ mol) \times 8.3145\ J K^{-1}\ mol^{-1} \times 100\ K=-831\ J\\\\\Delta U= q+w=(28.8 -0.831)\ KJ= 27.969\ KJ\\\\$

For question b:

In this question, the energy and enthalpy of a perfect gas depend on temperature alone, therefore $\Delta H= 28.8 \ KJ$ and $\Delta U= 27.969\ KJ$ as above at constant volume $w=0$ and $\Delta U=q$ so, $q=27.969 \ KJ$ .

Learn more:

brainly.com/question/4270867

6 0

3 years ago