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notka56 [123]
3 years ago
14

Which of these molecules has the same number of shared electron pairs as unshared electron pairs? (a) hcl, (b) h2s, (c) pf3, (d)

ccl2f2 (e) br2?
Chemistry
2 answers:
Paul [167]3 years ago
8 0
<span>H2S has 2 bonds which means that it has two shared electron pairs. It has 2 lone pairs on electrons. It's the only one where the 2 are the same.</span>
uranmaximum [27]3 years ago
7 0

Let us check each molecule

a) HCl : the number of shared electron pairs is "one"

the number of unshared electron pairs is six [on chlorine]

b) H₂S : the number of shared electron pairs is "two" as there are two bonds of sulphur with two hydrogen atoms.

The number of valence electrons on sulphur are six, out of these two are involved in bonding and rest four are in the form of two unshared (lone pair) pair of electrons

So in H₂S it has the same number of shared electron pairs as unshared electron pairs

c) PF₃ : the shared pair of electrons are "three"

the number of unshared electron pairs is one on phosphorous.

d) CCl₂F₂ : there are total four shared pair of electrons on carbon and zero unshared electron pairs

e) Br₂ : only one shared electron pair and three unshared electron pairs

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shepuryov [24]
You just need to multiply the terms and transform to kj by dividing by 1000
1) 10.4kj
2) 14.5 kj 
3) 44.8 kj
4) 1.04 kj

and there you go.
8 0
3 years ago
Read 2 more answers
Ammonia is produced industrially via this exothermic reaction.
Cloud [144]

Answer:

high pressure of 200-300 atm.

low temp. of between 400-500 degrees celsius:this is for continuous development of ammonia since it decomposes at high temp fathermore the reaction is exothermic

a catalyst to speed up the rate of reaction:i guess it is finely divided iron impregnated in aluminium oxide

platinum can be used as a catalyst but it is easily poisoned

hope it helps

Explanation:

6 0
2 years ago
Si desea preparar 300 gramos de una solución de azúcar en agua que tenga una concentración de 20% m/m en cuanto gramos de soluto
Digiron [165]

Answer:

m_{soluto}=60g

Explanation:

¡Hola!

En este caso, al considerar la unidad de concentración de porcentaje masa/masa, podemos escribir su fórmula como:

\%m/m=\frac{m_{soluto}}{m_{solucion}}*100\%

Podemos identificar la masa de soluto (azúcar) como la incógnita, y resolverla como se muestra a continuación:

m_{soluto}=\frac{\%m/m*m_{solucion}}{100\%}\\\\m_{soluto}=\frac{20\%*300g}{100\%}\\\\m_{soluto}=60g

¡Saludos!

5 0
2 years ago
Given that a for HBrO is 2. 8×10^−9 at 25°C. What is the value of b for BrO− at 25°C?
lara [203]

If Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

<h3>What is base dissociation constant? </h3>

The base dissociation constant (Kb) is defined as the measurement of the ions which base can dissociate or dissolve in the aqueous solution. The greater the value of base dissociation constant greater will be its basicity an strength.

The dissociation reaction of hydrogen cyanide can be given as

HCN --- (H+) + (CN-)

Given,

The value of Ka for HCN is 2.8× 10^(-9)

The correlation between base dissociation constant and acid dissociation constant is

Kw = Ka × Kb

Kw = 10^(-14)

Substituting values of Ka and Kw,

Kb = 10^(-14) /{2.8×10^(-9) }

= 3.5× 10^(-6)

Thus, we find that if Ka for HBrO is 2. 8×10^−9 at 25°C, then the value of Kb for BrO− at 25°C is 3.5× 10^(-6).

DISCLAIMER: The above question have mistake. The correct question is given as

Question:

Given that Ka for HBrO is 2. 8×10^−9 at 25°C. What is the value of Kb for BrO− at 25°C?

learn more about base dissociation constant:

brainly.com/question/9234362

#SPJ4

7 0
1 year ago
Whose work is credited with being the beginning of the modern atomic theory​
Damm [24]
Democritus (460-370 BC) was a Greek philosopher who theorized that all matter could be reduced to particles that could not be divided, which he described as “atomos.”

John Dalton (1766-1844) Proposed the atomic theory.

7 0
2 years ago
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