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3 years ago

What conditions make a pair of triangles congruent

Mathematics

1 answer:

Artemon [7]3 years ago

5 0

Two corresponding sides and two corresponding angles are congruent.

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For the data shown in the scatter plot below, identify a point apart from the main cluster

poizon [28]

The answer is (8, 7)

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3 years ago

when all the kids who tried out for soccer were divided into teams of 15 players, there were exactly eight teams. how many kids

seropon [69]

You would multiply 15 ×8= 120 kids tried out

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3 years ago

What are the vertices of triangle A'B'C' produced by (x, y) -> (x+5, y-2)?

lara [203]

Answer:

The vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

Step-by-step explanation:

Given the vertices of an original triangle ΔABC such that

A = (3, 0)

B = (3, 2)

C = (0, -3)

As the rule of translation is given by

Translation: (x, y) → (x+5, y-2)

So, after the translation the vertices of the original triangle ΔABC will be translated as:

A = (3, 0) → (x+5, y-2) ⇒ (3+5, 0-2) = A'(8, -2)

B = (3, 2) → (x+5, y-2) ⇒ (3+5, 2-2) = B'(8, 0)

C = (0, -3) → (x+5, y-2) ⇒ (0+5, -3-2) = C'(5, -5)

Therefore, the vertices of triangle A'B'C' produced by (x, y) → (x+5, y-2) will be:

A'(8, -2)

B'(8, 0)

C'(5, -5)

7 0

3 years ago

Ahoy there, matey! Our pirate ship had 5/6 of a treasure chest full of gold.

Kisachek [45]

Answer:

1 $\frac{5}{24}$ teasure chests of gold

Step-by-step explanation:

Since this is a problem of adding or subtracting fractions, you will have to do one or the other to solve. Since the pirates already had $\frac{5}{6}$ of a treasure chest of gold and stole another $\frac{3}{8}$ of a treasure chest to add to their collection, we need to add these two fractions:

$\frac{5}{6}+\frac{3}{8}$

In order to add or subtract fractions, you need to have a common denominator. Choosing a common denominator means looking for the lowest common multiple of the two denominators:

6: 6, 12, 18, 24

8: 8, 16, 24

$\frac{5}{6}=\frac{20}{24}and\frac{3}{8}=\frac{9}{24}$

Add them together: $\frac{20}{24}+\frac{9}{24}=\frac{29}{24}=1\frac{5}{24}$

7 0

3 years ago

About 13 out of 20 homes have a personal computer. On a street with 60 homes, how many would you to expect to have a personal co

GenaCL600 [577]

39 homes
because if you put in 60 for 20 you would have to multiply 3 to get 60 so you do 3x13 and it would equal 39

5 0

3 years ago

Read 2 more answers