Look at the attachment
The line bisects the cord which we have to find
- Length of chord=12cm
- Half of the cord=12/2=6cm
- Radius=10cm
Its a right angle triangle
- using Pythagorean theorem
![\boxed{\sf P^2=H^2-B^2}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%20P%5E2%3DH%5E2-B%5E2%7D)
![\\ \Large\sf\longmapsto P=\sqrt{H^2-B^2}](https://tex.z-dn.net/?f=%5C%5C%20%5CLarge%5Csf%5Clongmapsto%20P%3D%5Csqrt%7BH%5E2-B%5E2%7D)
![\\ \Large\sf\longmapsto P=\sqrt{10^2-6^2}](https://tex.z-dn.net/?f=%5C%5C%20%5CLarge%5Csf%5Clongmapsto%20P%3D%5Csqrt%7B10%5E2-6%5E2%7D)
![\\ \Large\sf\longmapsto P=\sqrt{100-36}](https://tex.z-dn.net/?f=%5C%5C%20%5CLarge%5Csf%5Clongmapsto%20P%3D%5Csqrt%7B100-36%7D)
![\\ \Large\sf\longmapsto P=\sqrt{64}](https://tex.z-dn.net/?f=%5C%5C%20%5CLarge%5Csf%5Clongmapsto%20P%3D%5Csqrt%7B64%7D)
![\\ \Large\sf\longmapsto P=8cm](https://tex.z-dn.net/?f=%5C%5C%20%5CLarge%5Csf%5Clongmapsto%20P%3D8cm)
Distance of the chord from centre is 8cm.
The GRE Scores are represented as ~N(310,12)
In order to find the proportion of scores between 286 and 322, we need to standardize the scores so we can use the standard normal probabilities. Thus, we will find the z-score.
![z-score = \frac{286 - 310}{12} = -2](https://tex.z-dn.net/?f=z-score%20%3D%20%20%5Cfrac%7B286%20-%20310%7D%7B12%7D%20%3D%20%20-2)
![z-score = \frac{322 - 310}{12} = 1](https://tex.z-dn.net/?f=z-score%20%3D%20%20%5Cfrac%7B322%20-%20310%7D%7B12%7D%20%3D%201%20)
By looking on the standard normal probabilities table, we find the proportion of scores less than -2.
P(z < -2) = 0.0228
Then, we find the proportion of scores less than 1.
P(z < 1) = 0.8413
To find the proportion between -2 and 1, we subtract the two.
P(-2 < z < 1) = 0.8413 - 0.0228 = 0.8185 = 81.85%
Therefore, 82% of scores are between 286 and 322
Answer:
b
Step-by-step explanation:
735\
Yes.
The prime factorization is ...
84 = 2² × 3 × 7
Answer:
slader app helps
Step-by-step explanation: