Given:
AB= 20, BV=12, VA=14 and SR is a mid segment.
To find:
The lengths of SR and AR.
Solution:
SR is a mid segment. So, SR is parallel to the non-included side BV and the length of SR is half of BV.
SR is a mid segment. So, it divides the included sides in two equal parts. It means R is the midpoint of VA.
Therefore, the measure of SR is 6 units and the measure of AR is 7 units.
Answer:
It will be an equilateral triangle and the area is 1924.5 sq. meters.
Step-by-step explanation:
If the total length of the fencing of 200 meters is utilized then the perimeter of the triangle will be 200 meters.
Now, we know that the type of triangle that gives the maximum area for a given perimeter is an equilateral triangle.
So, the equilateral triangle with a perimeter of 200 meters will have side lengths of meters.
Now, the area of an equilateral triangle with sides a units is given by sq. units.
So, the area of the above equilateral triangle will be = sq. meters. (Answer)