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3 years ago

How many roots do the following equations have? -12x2 - 25x + 5 + x3 = 0

Mathematics

2 answers:

frozen [14]3 years ago

7 0

The answer issssss 3!!!!

Luden [163]3 years ago

3 0

Answer: The equations have 3 roots.
x=-1.971, 0.184, and 13.787
Please, see the attached file.
Thanks.

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CAN ANYONE HELP ME ANSWER THIS PLEASE

HACTEHA [7]

Answer: 14/45

Step-by-step explanation: The probability that they first event will occur is 2/10. The probability that the second event will occur is 1/9. If you multiply those like it says in the hint you will get 14/45. (I think this is right)

5 0

3 years ago

Suppose h(x)=3x-2 and j(x) = ax +b. Find a relationship between a and b such that h(j(x)) = j(h(x))

sergejj [24]

Answer:

$\displaystyle a = \frac{1}{3} \text{ and } b = \frac{2}{3}$

Step-by-step explanation:

We can use the definition of inverse functions. Recall that if two functions, f and g are inverses, then:

$\displaystyle f(g(x)) = g(f(x)) = x$

So, we can let j be the inverse function of h.

Function h is given by:

$\displaystyle h(x) = y = 3x-2$

Find its inverse. Flip variables:

$x = 3y - 2$

Solve for y. Add:

$\displaystyle x + 2 = 3y$

Hence:

$\displaystyle h^{-1}(x) = j(x) = \frac{x+2}{3} = \frac{1}{3} x + \frac{2}{3}$

Therefore, a = 1/3 and b = 2/3.

We can verify our solution:

$\displaystyle \begin{aligned} h(j(x)) &= h\left( \frac{1}{3} x + \frac{2}{3}\right) \\ \\ &= 3\left(\frac{1}{3}x + \frac{2}{3}\right) -2 \\ \\ &= (x + 2) -2 \\ \\ &= x \end{aligned}$

And:

$\displaystyle \begin{aligned} j(h(x)) &= j\left(3x-2\right) \\ \\ &= \frac{1}{3}\left( 3x-2\right)+\frac{2}{3} \\ \\ &=\left( x- \frac{2}{3}\right) + \frac{2}{3} \\ \\ &= x \stackrel{\checkmark}{=} x\end{aligned}$

3 0

2 years ago

Marcus completed 187 jumping jacks in 3 days. He completed 60 jumping jacks on each of the first 2 days, and y number of jumping

grandymaker [24]

B..................................................

8 0

3 years ago

Read 2 more answers

Will ran the diagonal distance across a square field measuring 40 yards on each side. James ran the diagonal distance across a r

slamgirl [31]

Will ran the longest

He ran for 56.57 yards, 13.56 yards longer than James.

Step-by-step explanation:

Step 1 :

Will ran the diagonal across a square field measuring 40 yards in each side.

The diagonal of a square can be obtained by the square root of the sum of the squares of its 2 sides [Because it forms the hypotenuse of a right angle triangle]

Hence when the side is 40 yards , the diagonal would be

$\sqrt{40^{2} + 40^{2}} = \sqrt{1600 + 1600} = \sqrt{3200} =56.57 yards$

So Will ran for 56.57 yards

Step 2 :

James ran the diagonal of a rectangular field with 25 yards length and 35 yards width.

The diagonal of the rectangle can be obtained by the square root of the sum of squares of its length and width.

Hence when the length is 25 yards and width is 35 , the diagonal would be

$\sqrt{35^{2} + 25^{2}} = \sqrt{1225 + 625}} = \sqrt{1850} = 43.01$ yards

So James ran for 43.01 yards

Step 3 :

Will ran for 56.57 yards and 43.01 yards.

Hence Will ran for longer distance of 56.57 yards, which is 13.56 yards more than James.

5 0

3 years ago

Please help

Aloiza [94]

A=10x(15x)-p(4x)^2

A=150x^2-16px^2

A=(150-16p)x^2

6 0

3 years ago