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lorasvet [3.4K]
3 years ago
8

Solve: 2m - 8 = -m + 10

Mathematics
2 answers:
Varvara68 [4.7K]3 years ago
6 0

Step-by-step explanation:

2m+m=10+8

3m=18 /3

M=6

Dimas [21]3 years ago
5 0

Step-by-step explanation:

2m - 8 =  - m + 10 \\ 2m + m = 10 + 8 \\  3m = 18 \\  \frac{3m}{3}  =  \frac{18}{3}  \\ m = 6

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In triangle abc shown below side ab is 6 and side ac is 4
kaheart [24]

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove  that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

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3 years ago
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Answer:

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Answer:

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Step-by-step explanation:

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