Answer:
(67/100)×(3/10)= (67x3)/(100×10)=201/1000=201/1000=0.201
Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

So, the mean of 11 consecutive integers is the 6th integer.
Answer:
a=9
Step-by-step explanation:
To solve this proportion, we have to get the variable, a, by itself.
First, cross multiply.
6/a=18/27
Multiply the denominator of the first fraction by the numerator of the second, and the numerator of the second by the denominator of the first.
a*18=6*27
18a=162
Now, 18 and a are being multiplied. In order to get a by itself, perform the opposite of what is being done. They are being multiplied, so the opposite would be division. Divide both sides by 18.
18a/18=162/18
a=162/18
a=9
So, the proportion, with 9 substituted in for a, will be:
6/9=18/27
Answer
(a) 
(b) 
Step-by-step explanation:
(a)
δ(t)
where δ(t) = unit impulse function
The Laplace transform of function f(t) is given as:

where a = ∞
=> 
where d(t) = δ(t)
=> 
Integrating, we have:
=> 
Inputting the boundary conditions t = a = ∞, t = 0:

(b) 
The Laplace transform of function f(t) is given as:



Integrating, we have:
![F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.](https://tex.z-dn.net/?f=F%28s%29%20%3D%20%5B%5Cfrac%7B-e%5E%7B-%28s%20%2B%201%29t%7D%7D%20%7Bs%20%2B%201%7D%20-%20%5Cfrac%7B4e%5E%7B-%28s%20%2B%204%29%7D%7D%7Bs%20%2B%204%7D%20-%20%5Cfrac%7B%283%28s%20%2B%201%29t%20%2B%201%29e%5E%7B-3%28s%20%2B%201%29t%7D%29%7D%7B9%28s%20%2B%201%29%5E2%7D%5D%20%5Cleft%20%5C%7B%20%7B%7Ba%7D%20%5Catop%20%7B0%7D%7D%20%5Cright.)
Inputting the boundary condition, t = a = ∞, t = 0:
