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3 years ago

Factor 1

Mathematics

2 answers:

zhuklara [117]3 years ago

6 0

Answer:

$\boxed{(x-2)(x-5)}$

Step-by-step explanation:

=> $x^2-7x+10$

Using mid-term break formula

=> $x^2-5x-2x+10$

=> x(x-5)-2(x-5)

Taking (x-5) as common

=> (x-2)(x-5)

Thepotemich [5.8K]3 years ago

3 0

Answer:

Step-by-step explanation:

$x^2 - 7x + 10=\\\\=x^2 - 5x -2x + 10=\\\\=x(x-5)-2(x-5)=\\\\=(x-5)(x-2)$

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Note: Enter your answer and show all the steps you use to solve this problem in the space provided.

Alex Ar [27]

Answer:

(67/100)×(3/10)= (67x3)/(100×10)=201/1000=201/1000=0.201

7 0

3 years ago

44,880 2 poir 8) A pen cost $39 and a pencil cost $17 less. What is the total cost of one pen and two pencils? *

wariber [46]

Answer:

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7 0

2 years ago

What is the average (arithmetic mean) of eleven consecutive integers? (1) the average of the first nine integers is 7. (2) the a

laiz [17]

Since eleven is odd, there must be a centra element, which in this case is the sixth. So, we can write 11 consecutive integers as

$x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5$

Since the arithmetic mean is the sum of the values, divided by how many they are, we have

$M = \dfrac{x-5, x-4, x-3, x-2, x-1, x, x+1, x+2, x+3, x+4, x+5}{11} = \dfrac{11x}{11} = x$

So, the mean of 11 consecutive integers is the 6th integer.

4 0

3 years ago

What is the solution of the proportion? 6/a = 18/27

Marta_Voda [28]

Answer:

a=9

Step-by-step explanation:

To solve this proportion, we have to get the variable, a, by itself.

First, cross multiply.

6/a=18/27

Multiply the denominator of the first fraction by the numerator of the second, and the numerator of the second by the denominator of the first.

a*18=6*27

18a=162

Now, 18 and a are being multiplied. In order to get a by itself, perform the opposite of what is being done. They are being multiplied, so the opposite would be division. Divide both sides by 18.

18a/18=162/18

a=162/18

a=9

So, the proportion, with 9 substituted in for a, will be:

6/9=18/27

6 0

3 years ago

Read 2 more answers

(5) Find the Laplace transform of the following time functions: (a) f(t) = 20.5 + 10t + t 2 + δ(t), where δ(t) is the unit impul

Aloiza [94]

Answer

(a) $F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

Step-by-step explanation:

(a) $f(t) = 20.5 + 10t + t^2 +$ δ(t)

where δ(t) = unit impulse function

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 f(s)e^{-st} \, dt$

where a = ∞

=> $F(s) = \int\limits^a_0 {(20.5 + 10t + t^2 + d(t))e^{-st} \, dt$

where d(t) = δ(t)

=> $F(s) = \int\limits^a_0 {(20.5e^{-st} + 10te^{-st} + t^2e^{-st} + d(t)e^{-st}) \, dt$

Integrating, we have:

=> $F(s) = (20.5\frac{e^{-st}}{s} - 10\frac{(t + 1)e^{-st}}{s^2} - \frac{(st(st + 2) + 2)e^{-st}}{s^3} )\left \{ {{a} \atop {0}} \right.$

Inputting the boundary conditions t = a = ∞, t = 0:

$F(s) = \frac{20.5}{s} - \frac{10}{s^2} - \frac{2}{s^3}$

(b) $f(t) = e^{-t} + 4e^{-4t} + te^{-3t}$

The Laplace transform of function f(t) is given as:

$F(s) = \int\limits^a_0 (e^{-t} + 4e^{-4t} + te^{-3t} )e^{-st} \, dt$

$F(s) = \int\limits^a_0 (e^{-t}e^{-st} + 4e^{-4t}e^{-st} + te^{-3t}e^{-st} ) \, dt$

$F(s) = \int\limits^a_0 (e^{-t(1 + s)} + 4e^{-t(4 + s)} + te^{-t(3 + s)} ) \, dt$

Integrating, we have:

$F(s) = [\frac{-e^{-(s + 1)t}} {s + 1} - \frac{4e^{-(s + 4)}}{s + 4} - \frac{(3(s + 1)t + 1)e^{-3(s + 1)t})}{9(s + 1)^2}] \left \{ {{a} \atop {0}} \right.$

Inputting the boundary condition, t = a = ∞, t = 0:

$F(s) = \frac{-1}{s + 1} - \frac{4}{s + 4} - \frac{4}{9(s + 1)^2}$

3 0

3 years ago