Let X and Y be random variables representing the side lengths of the rectangle. Then the area of the rectangle is given by the random variable XY.
We have

or approximately 0.1534.
How far did the frog jump? the answer is one of the solutions of the quadratic equation

because that's where the frogs height is 0 (y=0) feet.
Use your favorite formula for quadratic equations. I got two solutions: 0 and 30. 0 is clearly the starting point and 30 feet is point where the frog lands.
The height is the maximum of the quadratic form. Use the formula for maximum x of a quadratic: xmax = -b/(2a) = -0.51/(2*0.017) = 15. The maximum at that point is ymax = 3.825
So, the correct answer is (a) 30 ft far and 3.83 high.
Six (6) less than (subtraction) six (6) times (multiplication) a number (n) is (=) 12.
6n - 6 = 12
To solve, add 6 to both sides
6n = 18 Dviide both sides by 6
n = 3
Answer:
The multiplicative rate of change is 3/4
Step-by-step explanation:
Here, we want to get the multiplicative rate of change
In this case, by dividing the succeeding term by the preceding term, we will get the multiplicative rate of change
mathematically, we have this as;
81/128 divided 27/32
= 81/128 * 32/27
= 3/4