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quester [9]
3 years ago
10

Which is a true statement?

Physics
1 answer:
aivan3 [116]3 years ago
8 0
Hi! The answer is ‘B’! Because the nucleus is found at the center and contains protons (positive charge) and neutrons (no charge)
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Which is not a principle of fitness?<br> Overload<br> Height<br> Specificity<br> Individuality
Nitella [24]

Answer:

Height

Explanation:

7 0
3 years ago
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If 250 g of calcium chlorate decomposes into calcium chloride and oxygen, what mass of oxygen would be produced?
sineoko [7]

115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

<u>Explanation:</u>

Ca(ClO₃)₂ -->CaCl₂ + 3O₂

One mole of calcium chlorate give three moles of oxygen.

Molar mass of calcium chlorate is

40+(35.5+16*3)*2 = 207g/mol

Molar mass of Oxygen = 32g

1 mole of calcium chlorate decomposes to form 3 moles of oxygen.

So,

207g of Ca(ClO₃)₂ produces 3 X 32g of O₂

250g of Ca(ClO₃)₂ will produce = \frac{3 X 32}{207} X 250

                                                    = 115.94g of O₂

Therefore, 115.94g of O₂ are produced by 250g of Ca(ClO₃)₂

7 0
4 years ago
Bungee jumping is an example of
Shtirlitz [24]
I think it’s c gravitational and elastic energy
5 0
3 years ago
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I was driving 150 km/hr for 20 km, then had to pull over for a quarter of an hour to replace my tire, and then drove the last 3.
Likurg_2 [28]

Answer:

ertyu

Explanation:

4 0
3 years ago
A 1.25 x 10-4 C charge is moving5200 m/s at 37.0° to a magnetic fieldof 8.49 x 10-4 T. What is the magneticforce on the charge?
juin [17]

0.0003321 Newtons

Explanation

We are given the charge, its velocity, and the magnetic field strength and direction. We can thus use the equation to find the force

\begin{gathered} F=qvBsinθ \\ where\text{ F is the magnetic force} \\ q\text{ is the charge} \\ v\text{ is the velocity of the charge} \\ Bis\text{ the magnetic field} \\ \theta\text{ is the angle} \end{gathered}

so

Step 1

Let

\begin{gathered} q=1.25*10^{-4\text{ }}C \\ v=5200\frac{m}{s} \\ \theta=37\text{ \degree} \\ B=8.49*10^{-4}T \end{gathered}

now, replace

\begin{gathered} F=qvBs\imaginaryI n\theta \\ F=1.25*10^{-4}\text{ C*5200 }\frac{m}{s}*8.49*10^{-4}Tsin(37) \\ F=0.0003321\text{ Newtons} \\  \end{gathered}

so, the answer is

0.0003321 Newtons

I hope this helps you

7 0
1 year ago
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