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Kaylis [27]
3 years ago
11

Which of the following statements must be true?

Physics
1 answer:
anyanavicka [17]3 years ago
6 0

Answer:

your answer is B. The velocity could be in any direction, but the acceleration is in the direction of the resultant force

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A box is being pushed from the left with a force of 5 N. No force is being applied from the right.
Sergio039 [100]

Answer:

The box will move to the right with increasing speed

Explanation:

According to Newton's second law:

F=ma (1)

where

F is the net force on an object

m is the mass of the object

a is its acceleration

For the box in this problem, there is only one force acting on it: a force of 5 N from the left (so, to the right). This means that according to (1) the box will experience an acceleration: the direction of the acceleration is the same as the direction of the net force (so, to the right), therefore the box will move to the right and its speed will continue increasing due to fact that it is being accelerated.

6 0
3 years ago
A hockey puck is struck so that it slides at a constant speed and strikes the far side of the rink, 58.2 m away. The shooter hea
DENIUS [597]

Answer:

v = 33.66 m/s

Explanation:

Let hockey puck is moving at constant speed v

so here we have

d = vt

so time taken by the puck to strike the wall is given as

t = \frac{58.2}{v}

now time taken by sound to come back at the position of shooter is given as

t_2 = \frac{58.2}{340}

t_2 = 0.17s

so we know that total time is 1.9 s

1.9 = t + t_2

1.9 = t + 0.17

1.9 - 0.17 = t

t = 1.73 s

now we have

1.73 = \frac{58.2}{v}

v = 33.66 m/s

7 0
3 years ago
The windshield of a car has a total length of arm and blade of 9 ​inches, and rotates back and forth through an angle of 93degre
Sergio039 [100]

Answer:

The area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

Explanation:

Given

Length of blade = 9 inches

Angle of rotation = 93°

We're to calculate the area of the portion of the windshield cleaned by the 7​-in wiper​ blade?

We'll solve this by using area of a sector.

Area of a sector = ½r²θ

where θ is in radians.

So, angle of rotation (93°) must first be converted to radians

Converting 93º to radians, we get 31π/60

The area of the region swept out by the wiper blade = (area of the sector where r = 9 and

θ = 31π/60) - (area of the sector where r = (9-7) and θ = 31π/60).

We're making use of 9-7 because that region is outside the boundary of the 7in blade

So Area = ½*9²*31π/60 - ½*2²*31π/60

Area = ½*31π/60(9²-7²)

Area = 31π/120 * (81 - 49)

Area = 31π/120 * 32

Area = 992π/120

Area = 62.49151386765697 in²

Area ≈ 62.49 in²

Hence, the area of the portion of the windshield cleaned by the 7-in wiper blade is 62.49 in²

5 0
3 years ago
Read 2 more answers
You're carrying a 3.2-m-long, 24kg pole to a construction site when you decide to stop for a rest. You place one end of the pole
Aleksandr [31]

Answer:

Tension of 132N

Explanation:

We need to apply Summatory of Force to find the tension in the hand.

We define te tensión in the hand as F_2 and the Tension in fence post as F_1, then

\sum F = 24(9.8)

F_1 + F_2= 24(9.8)

We apply summatory of moments then

F_2*1.25 = F_1*1.6

Where the Force 2 is 1.25m from the center of summatory,

We can note that,

1.6 m - 0.35m=1.25m

We have two equation and two incognites, then replacing (1) in (2)

1.6(235.2 -F_2) = 1.25F_2

376.32 = F2(1.6+1.25)

F_2= \frac{376.32}{2.85}

F_2 =132 N

5 0
3 years ago
The chart shows data for a moving object.
Ipatiy [6.2K]

Answer:

number 2

Explanation:

8 0
3 years ago
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