Answer:
B. 4/3
Step-by-step explanation:
slope-intercept formula is y=mx+b, where m is the slope and y has to be by itself.
dividing 4 by 3 cant be more simplified than 4/3.
Answer:
a=1 or a=5/6
Step-by-step explanation:
I'm going to attempt to factor 6a^2-a-5
a=6
b=-1
c=-5
Find two numbers that multiply to be a*c and add to be b.
a*c=-30 =-6(5)
b=-1 =-6+5
So replace -a with -6a+5a in the expression we started with
6a^2-6a+5a-5
now we factor by grouping
6a(a-1)+5(a-1)
(a-1)(6a-5)
Now let's solve the equation:
(a-1)(6a-5)=0
So a=1 or a=5/6
Answer:
15.14%
Step-by-step explanation:
The formula for APR is stated thus:
APR=fees+interest/principal/n*365*100
principal is the loan amount of $700
fees is the processing fees on the loan which is $50
interest amount=principal*interest %=$700*8%=$56
n is the number of days of the loan which is a year i.e 365 days
APR=($50+$56)/$700/365*365*100
APR=$106/$700/365*365*100
APR=0.151428571
/365*365*100
APR=0.151428571
*100=15.14%
The annual percentage rate on the loan is 15.14% which represents the actual cost on the loan not just the interest cost of 8% annually
Answer:
a rectangle is twice as long as it is wide . if both its dimensions are increased 4 m , its area is increaed by 88 m squared make a sketch and find its original dimensions of the original rectangle
Step-by-step explanation:
Let l = the original length of the original rectangle
Let w = the original width of the original rectangle
From the description of the problem, we can construct the following two equations
l=2*w (Equation #1)
(l+4)*(w+4)=l*w+88 (Equation #2)
Substitute equation #1 into equation #2
(2w+4)*(w+4)=(2w*w)+88
2w^2+4w+8w+16=2w^2+88
collect like terms on the same side of the equation
2w^2+2w^2 +12w+16-88=0
4w^2+12w-72=0
Since 4 is afactor of each term, divide both sides of the equation by 4
w^2+3w-18=0
The quadratic equation can be factored into (w+6)*(w-3)=0
Therefore w=-6 or w=3
w=-6 can be rejected because the length of a rectangle can't be negative so
w=3 and from equation #1 l=2*w=2*3=6
I hope that this helps. The difficult part of the problem probably was to construct equation #1 and to factor the equation after performing all of the arithmetic operations.
